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MA 08Geometry. 7.5 Volume of Prisms and Cylinders. Goals. Find the volume of prisms. Find the volume of cylinders. Solve problems using volume. Volume. The number of cubic units contained in a solid. Measured in cubic units. Basic Formula: V = Bh B = area of the base, h = height.
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MA 08Geometry 7.5 Volume of Prisms and Cylinders
Goals • Find the volume of prisms. • Find the volume of cylinders. • Solve problems using volume. Geometry 12.4 Volume of Prisms and Cylinders
Volume • The number of cubic units contained in a solid. • Measured in cubic units. • Basic Formula: V = Bh • B = area of the base, h = height Geometry 12.4 Volume of Prisms and Cylinders
Cubic Unit V = s3 V = 1 cu. unit s 1 1 s 1 s Geometry 12.4 Volume of Prisms and Cylinders
Prism: V = Bh B B h h h B Geometry 12.4 Volume of Prisms and Cylinders
Cylinder: V = r2h r B h h V = Bh Geometry 12.4 Volume of Prisms and Cylinders
8 3 10 Example 1 Find the volume. Triangular Prism V = Bh Base = 40 V = 40(3) = 120 Abase = ½ (10)(8) = 40 Geometry 12.4 Volume of Prisms and Cylinders
Example 3 A soda can measures 4.5 inches high and the diameter is 2.5 inches. Find the approximate volume. V = r2h V = (1.252)(4.5) V 22 in3 (The diameter is 2.5 in. The radius is 2.5 ÷ 2 inches.) Geometry 12.4 Volume of Prisms and Cylinders
Example 4 A wedding cake has three layers. The top cake has a diameter of 8 inches, and is 3 inches deep. The middle cake is 12 inches in diameter, and is 4 inches deep. The bottom cake is 14 inches in diameter and is 6 inches deep. Find the volume of the entire cake, ignoring the icing. Geometry 12.4 Volume of Prisms and Cylinders
Example 4 Solution VTop = (42)(3) = 48 150.8 in3 VMid = (62)(4) = 144 452.4 in3 VBot = (72)(6) = 294 923.6 in3 r = 4 8 3 r = 6 12 4 486 1526.8 in3 14 6 r = 7 Geometry 12.4 Volume of Prisms and Cylinders
Concrete Pipe Geometry 12.4 Volume of Prisms and Cylinders
Example 5 A manufacturer of concrete sewer pipe makes a pipe segment that has an outside diameter (o.d.) of 48 inches, an inside diameter (i.d.) of 44 inches, and a length of 52 inches. Determine the volume of concrete needed to make one pipe segment. 48 44 52 Geometry 12.4 Volume of Prisms and Cylinders
View of the Base Example 5 Solution Strategy: Find the area of the ring at the top, which is the area of the base, B, and multiply by the height. Geometry 12.4 Volume of Prisms and Cylinders
Example 5 Solution Strategy: Find the area of the ring at the top, which is the area of the base, B, and multiply by the height. Area of Outer Circle: Aout = (242) = 576 Area of Inner Circle: Ain = (222) = 484 Area of Base (Ring): ABase = 576 - 484 = 92 48 44 52 Geometry 12.4 Volume of Prisms and Cylinders
Example 5 Solution V = Bh ABase = B = 92 V = (92)(52) V = 4784 V 15,021.8 in3 48 44 52 Geometry 12.4 Volume of Prisms and Cylinders
Example 6 4 5 L A metal bar has a volume of 2400 cm3. The sides of the base measure 4 cm by 5 cm. Determine the length of the bar. Geometry 12.4 Volume of Prisms and Cylinders
V = L W H 2400 = L 4 5 2400 = 20L L = 120 cm Example 6 Solution 4 5 L Geometry 12.4 Volume of Prisms and Cylinders
Summary • The volumes of prisms and cylinders are essentially the same: V = Bh & V = r2h • where B is the area of the base, h is the height of the prism or cylinder. • Use what you already know about area of polygons and circles for B. Geometry 12.4 Volume of Prisms and Cylinders
r B h h V = r2h V = Bh These are on your reference sheet. Geometry 12.4 Volume of Prisms and Cylinders
2.3 in 4 in 4.5 in 3.2 in 1.6 in Which Holds More? This one! Geometry 12.4 Volume of Prisms and Cylinders
What would the height of cylinder 2 have to be to have the same volume as cylinder 1? r = 3 r = 4 #2 #1 8 h Geometry 12.4 Volume of Prisms and Cylinders
Solution r = 4 #1 8 Geometry 12.4 Volume of Prisms and Cylinders
Solution r = 3 #2 h Geometry 12.4 Volume of Prisms and Cylinders