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Chapter 11. Test Thursday. Layout. 3 pressure conversions 2 temperature conversions 3 STP 3 manometer (1 closed, 2 open) 1 of each gas law: Dalton, Boyle, Charles, Gay-Lussac, Combined, Avogadro, ideal, non-ideal, effusion 2 bonus. Pressure conversions. 89 atm to Pa 78 Pa to kPa
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Chapter 11 Test Thursday
Layout • 3 pressure conversions • 2 temperature conversions • 3 STP • 3 manometer (1 closed, 2 open) • 1 of each gas law: Dalton, Boyle, Charles, Gay-Lussac, Combined, Avogadro, ideal, non-ideal, effusion • 2 bonus
Pressure conversions • 89 atm to Pa • 78 Pa to kPa • 670 mmHg to atm • 7912 mm Hg to torr • 8194 kPa to atm • 892 kPa to torr
Temperature conversions • Convert to Kelvin • 791 degrees Celsius • 8329 degrees Celsius • 2782 degrees Celsius • -14 degrees Celsius • -728 degrees Celsius
STP • P of STP • T of STP • V of STP
Manometer • Closed with Hg 207 mm higher on atm side • Closed with Hg 72 mm higher on atm side • Open with Hg 789 mm higher on gas side • Open with Hg 892 mm higher on atm side • Open with equal levels of Hg
Dalton • What is P gas when • P water = 278 torr • P water = 819 Pa • P water = 78 kPa • P water = 0.25 atm
Boyle • 1 example • If P = 5 atm, V1= 3 L and V2 = 60 L • V if V1 = 8 ml, P1 = 7 mm Hg, P2 = 82 mm Hg • V1 if V2 = 6 L, P1 = 4 torr, P2 = 40 torr
Charles • 1 example • V1 if V2 = 60 L, T1 = 7 K, T2 = 84 K • V1 if V2 = 60 L, T1 = 5 degrees Celsius, T2 = 10 degrees Celsius • V2 if V1 = 40 cc, T1 = 30 degrees Celsius, T2 = 60 degrees Celsius
Gay Lussac • P1 if P2 = 6 atm, T1 = 40 degrees Celsius, T2 + 78 degrees Celsius • P2 if P1 = 73 torr, T1 = 73 K, T2 = 96K • T1 if T2 = 60 degrees Celsius, and pressure is doubled
Combined • From STP to P = 4 atm, T = 900 K • From STP to doubling the P and T • From STP to tripling the P and V
Avogadro • V1 is STP, V2 is 44.8 L, n1 = 4 moles • V1 if V2 = 6 cc, n1 = 9 moles, n2 = 27 moles • Moles double
Ideal • P = 5 atm, V = , n = 2 moles, T = 50 degrees Celsius • P = 6 mm Hg, V = 4 L, n = 8 moles, T = • P = if V= 9 L, n = 10 moles, T = 5 K
Non-ideal • Solve for T if P = 5 atm, V = 4 L, n = 2 moles, a = 1, b = 2 • Solve for P • Solve for n • Solve for V
Effusion • A is 60 times faster than b and has a mass of 81 g. mass b = • A is 50 times slower than b and b’s mass is 36 g • A is twice as fast as b and has a mass of 25 g