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The Logic of Equation Solving

The Logic of Equation Solving. Lesson 3.4. Addition Property of Equality. Multiplication Property of Equality. f(x) = g(x) ↔ f(x) + h(x) = g(x) + h(x) If h ≠ 0, then, f(x) = g(x) ↔ f(x) • h(x) = g(x) • h(x). Example 1. Solve . Identify the property

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The Logic of Equation Solving

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  1. The Logic of Equation Solving Lesson 3.4

  2. Addition Property of Equality Multiplication Property of Equality f(x) = g(x) ↔ f(x) + h(x) = g(x) + h(x) If h ≠ 0, then, f(x) = g(x) ↔ f(x) • h(x) = g(x) • h(x)

  3. Example 1 Solve . Identify the property used to justify each step. Conclusion: Justification: x4-18 = 3(2x2+3) - mult. Prop. Of equ. x4-18 = 6x2+9 - distributive prop. x4- 6x2 -27 =0 - addition prop. (x2-9)(x2+3) = 0 - distributive prop x = 3, x = -3 - zero product. Check; both work!

  4. You try! -2(x2-8x+15) = 2x – 6 -mult. Prop. -2x2+16x-30 = 2x – 6 - dist. Prop. -2x2+14x -24 = 0 -add. Prop -2(x2-7x+12) = 0 -dist. Prop -2(x-3)(x-4) = 0 -dist. Prop x = 3, x = 4 -zero product. 3 doesn’t work!! x = 4

  5. Reversible steps vs. Irreversible • Reversible  they are bi-conditional (can be undone) • Irreversible  true conditional (if-then) statements for which the converse is false • Squaring both sides • Taking the log of both sides • Taking the square root of both sides • Multiplying out the denominator • If a function is 1-1, then the step is reversible. (x3, )

  6. Example 3 Find all real numbers x satisfying 32x-5 = 2187 Log32187 =2x-5 change to log Log2187/log3 =2x-5 change of base 7 = 2x – 5 12 = 2x addition x = 6 mult.

  7. Homework Pages 170 – 171 4-9, 11-15 20 - 24

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