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Steps for Solving a

Steps for Solving a. Stoichiometry Problem. By: Aryn Balogh Period: 1. If 12.7g of water is decomposed using an electric current, how many grams of Hydrogen and Oxygen gas will be produced?. Step 1: Write a complete and balanced chemical equation.

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Steps for Solving a

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  1. Steps for Solving a Stoichiometry Problem By: Aryn Balogh Period: 1

  2. If 12.7g of water is decomposed using an electric current, how many grams of Hydrogen and Oxygen gas will be produced?

  3. Step 1:Write a complete and balanced chemical equation. 2H2O 2H2 + O2

  4. Step 2:Draw a column for each chemical. 2H2O 2H2 + O2

  5. Step 3: Write the amount given in the appropriate column. 2H2O 2H2 + O2 12.7g

  6. Step 4:Convert the amount given into moles. 2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles

  7. Step 5:Find moles for each of the other chemicals. a) In each of the other columns write the moles of given (x) a fraction. 2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles 0.705mx X/X 0.705mx X/X

  8. b) The numerator of the fraction is the coefficient of that column. 2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705m x 2/X= 0.705m x 1/X=

  9. c) The denominator of the fraction is the coefficient of the given column. 2H2O 2H2 + O2 0.705m x 1/2= 12.7g/1 x 1mole/18.0148g= 0.705m x 2/2=

  10. d) Do math and label as moles. 2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles 0.705m x 2/2= 0.705 moles 0.705m x 1/2= 0.353 moles

  11. Step 6:Convert all moles into grams. 2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles 0.705m x 2/2= 0.705 moles 0.705m x 1/2= 0.353 moles 0.705m/1 x 2.0158g/1m= 1.42g 0.353m/1 x 31.998g/1m= 11.3g

  12. Step 7:Verify the law of conservation of mass 2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles 0.705m x 2/2= 0.705 moles 0.705m x 1/2= 0.353 moles 0.705m/1 x 2.0158g/1m= 1.42g 0.353m/1 x 31.998g/1m= 11.3g 12.7g = 1.42g + 11.3g 12.7g = 12.7g 1.42g of Hydrogen gas will be produced & 11.3g of Oxygen will be produced.

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