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The circumference of the circle is 50  feet . The area of the shaded region = ________

example 1 :. The circumference of the circle is 50  feet . The area of the shaded region = ________. 50. The circumference of the circle is 50  feet . The area of the shaded region = ________. 50. C =  d = 50  therefore the diameter of the circle is 50 feet. 50.

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The circumference of the circle is 50  feet . The area of the shaded region = ________

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  1. example 1 : The circumference of the circle is 50 feet . The area of the shaded region = ________

  2. 50 The circumference of the circle is 50 feet . The area of the shaded region = ________ 50 C =  d = 50 therefore the diameter of the circle is 50 feet.

  3. 50 The circumference of the circle is 50 feet . The area of the shaded region = ________ 25 C =  d = 50 therefore the diameter of the circle is 50 feet and the radius is 25 feet .

  4. 50 50 The circumference of the circle is 50 feet . The area of the shaded region = ________ 25 C =  d = 50 therefore the diameter of the circle is 50 feet and the radius is 25 feet . The area of the circle =  (25)2 = 625  square feet the area of the square = 50x50 = 2500 square feet

  5. 50 50 The circumference of the circle is 50 feet . The area of the shaded region = ________ 25 C =  d = 50 therefore the diameter of the circle is 50 feet and the radius is 25 feet . The area of the circle =  (25)2 = 625  square feet 2500 square feet - 625  square feet

  6. 50 50 The circumference of the circle is 50 feet . The area of the shaded region =(2500 - 625  ) square feet 25 C =  d = 50 therefore the diameter of the circle is 50 feet and the radius is 25 feet . The area of the circle =  (25)2 = 625  square feet 2500 square feet - 625  square feet

  7. example 2 : The circumference of the circle is 50 feet . The area of the shaded region = ________

  8. The circumference of the circle is 50 feet . The area of the shaded region = ________ C =  d = 50 therefore the diameter of the circle is 50 feet.

  9. The circumference of the circle is 50 feet . The area of the shaded region = ________ 50 x C =  d = 50 therefore the diameter of the circle is 50 feet. x Let x = the side of the square

  10. The circumference of the circle is 50 feet . The area of the shaded region = ________ 50 x C =  d = 50 therefore the diameter of the circle is 50 feet. x Let x = the side of the square x2 + x2 = 502 = 2500 x2 = 1250 = the area of the square area of circle = 625 

  11. The circumference of the circle is 50 feet . The area of the shaded region = ________ 50 x C =  d = 50 therefore the diameter of the circle is 50 feet. x Let x = the side of the square x2 + x2 = 502 = 2500 x2 = 1250 = the area of the square area of circle = 625  - area of square = 1250

  12. The circumference of the circle is 50 feet . The area of the shaded region =(625  - 1250) sq feet 50 x C =  d = 50 therefore the diameter of the circle is 50 feet. x Let x = the side of the square x2 + x2 = 502 = 2500 x2 = 1250 = the area of the square area of circle = 625  - area of square = 1250

  13. example 3 : AB = 30 feet A 30 B What is the SUM of the areas of the purple squares?_________

  14. example 3 : AB = 30 feet A 30 x x B y y What is the SUM of the areas of the purple squares?_________ Let x = the length of the side of the large square and let y = the length of the side of the small square

  15. example 3 : AB = 30 feet A Area = x2 30 x x B y Area = y2 y What is the SUM of the areas of the purple squares? x2 + y2 Let x = the length of the side of the large square and let y = the length of the side of the small square

  16. example 3 : AB = 30 feet A Area = x2 30 x x B y Area = y2 y What is the SUM of the areas of the purple squares? x2 + y2 = 302 = 900 sq ft Let x = the length of the side of the large square and let y = the length of the side of the small square

  17. example 4 : 10 feet If the area of the triangle is 14 square feet, then the area of the rectangle is ____________ 7 feet

  18. example 4 : 10 feet If the area of the triangle is 14 square feet, then the area of the rectangle is ____________ The area of a triangle = ½ height x base 7 feet 14 = ½ height x 7 28 = height x 7 4 = height

  19. example 4 : 10 feet If the area of the triangle is 14 square feet, then the area of the rectangle is 10 x 4 = 40 sq ft 4 The area of a triangle = ½ height x base 7 feet 14 = ½ height x 7 28 = height x 7 4 = height

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