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polynomial function. n. lead. degree. a. coefficient. undefined. f(x) = 0. zero function. 0. f(x) = 5. constant function. 1. f(x) = 2x + 5. linear function. f(x) = x 2 + 2x + 5. 2. quadratic function. slope. linear. constant non-zero. roots or solutions. x = -1 or 3.5.
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polynomial function n lead degree a coefficient undefined f(x) = 0 zero function 0 f(x) = 5 constant function 1 f(x) = 2x + 5 linear function f(x) = x2 + 2x + 5 2 quadratic function slope linear constant non-zero
roots or solutions x = -1 or 3.5 vertex: (h, k) complete the square vertex: (–4, –1) axis of symmetry: x = –4
vertex: (1, 5) vertex: x – intercepts:
constants constant of variation or proportion power is proportional to varies as power function power: –4 constant of variation: 2 not a power function: power isn’t a constant power function independent variable: r power: 2 constant of variation: power is 1, constant of variation is 2 power is 2, constant of variation is 1 direct variation
d = k F d = k t 2 non-negative integer monomial degree: 0 lead coefficient: 4 not monomial power is ½ (not an integer) monomial degree: 3 lead coefficient: 13 not monomial power is a variable
vertical stretch / shrink vertical stretch / shrink reflection across the x-axis domain range continuity increasing decreasing symmetry boundedness extrema asymptotes end behavior
divisor dividend quotient remainder
(3)2 – 4(3) – 5 = 9 – 12 – 5 = –8 k = 3 (–2)2 – 4(–2) – 5 = 4 + 8 – 5 = 7 k = –2 (5)2 – 4(5) – 5 = 25 – 20 – 5 = 0 k = 5 divides evenly zero x - intercept solution root
so factors are: x + 4, x – 3, x + 1 3(x + 4)(x – 3)(x + 1) = 3x3 + 6x2 – 33x – 36 so factors are: x + 3, x + 2, x – 5 2(x + 3)(x + 2)(x – 5) = 2x3 – 38x – 60
f(x) = x2 – 16 (x + 4)(x – 4) = 0 x = 4, x = –4 rational zeros
Use the rational zeros theorem to find the rational zeros of f(x) = 2x3 + 3x2 – 8x + 3 p = integer factors of the constant q = integer factors of the lead coefficient potential:
complex (real and non-real) zeros * non-real zeros are not x – intercepts zeros: 3i, – 3i, – 5 x-intercepts: – 5 complex conjugate (a + bi and a – bi)
denominator the x – axis ( y = 0 ) the line y = an / bm there is no quotient output input
vertical asymptote: x – intercept none none y – intercept horizontal asymptote: y = 0 (0, 4) vertical asymptote: x – intercept x = –1 (0, 0) (1, 0) y – intercept horizontal asymptote: none (0, 0) slant asymptote: y = x – 2
(–3, 4) U (4, ) [ –3, ) (– , –3) (– , –3) because the graph crosses the x-axis because the graph does not cross the x-axis
–3 1 2 1, –3, 2 + – + + (– , –3) U (1, 2) U (2, ) (–3, 1)
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