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4.1 Detours and Midpoints. Homework Proof Problem #18. 18) Given: AD DB AE BC CD ED Prove: Δ AFB is isosceles. A. B. F. E. C. D. 18) Given: AD DB AE BC CD ED Prove: Δ AFB is isosceles. A. B. F. E. C. D. From our givens: Δ AED Δ BCD
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4.1 Detours and Midpoints Homework ProofProblem #18
18) Given: AD DB AE BC CD ED Prove: Δ AFB is isosceles A B F E C D
18) Given: AD DB AE BC CD ED Prove: Δ AFB is isosceles A B F E C D
From our givens: ΔAED ΔBCD by : SSS A B Now we have 3 pairs of corresponding congruent angles! E C D For our next pair of Δ’s we will need: ∡EDA ∡CDB by CPCTC
We have: ED DC AD DB and PART of the included angle between those two sides! A B 2 pairs of congruent sides We need the rest of ∡EDB and ∡CDA E C ∡ADB ∡ADB by REFLEXIVE PROPERTY That give us . . . ∡EDB ∡CDA by ADDITION D From these triangles, we get sides EB AC by CPCTC ΔEDB ΔCDA by SAS
We are getting closer to ΔAFB! A B For this pair of Δ’s, we already have: AE BC (Given) EB CA (CPCTC) F This means: ∡ABE ∡BAC by CPCTC E C We have another EASY side! AB AB by Reflexive Property Now we have proven: ΔEABΔCBA by SSS Look what we have!
A B It’s time for: F Theorem 21: (Angle-Side Theorem) If two angles of a triangle are congruent, the sides opposite the angles are congruent. So now we can say: AF BF Reason? IF , then And for our final “PROVE!” Statement: Δ AFB is ISOSCELES Reason:If a triangle has at least two congruent sides, then it is isosceles byDEFINITION!
Statements Reasons A B 1. AD DB (S) 1. Given 2. AE BC (S) 2. Given 3. CD ED (S) 3. Given F 4. Δ AED ΔBCD 4. SSS (1, 2, 3) 5. ∡ EDA ∡CDB 5. CPCTC E C 6. ∡ ADB ∡ADB 6. Reflexive Property 7. ∡EDB ∡CDA (A) 7. AdditionProperty D 8. Δ EDB ΔCDA 8. SAS (1, 7, 3) 9. EB CA 9. CPCTC 10. AB AB 10. Reflexive Property 11. Δ EAB ΔCBA 11. SSS (2, 10, 9) 12. ∡ ABE ∡BAC 12. CPCTC 13. BF AF 13. If , then 14. Δ AFB is isosceles 14. If a Δ has at least 2 sides, then isosceles!