1 / 7

Real-World Problems in Mathematics: Linear Functions & Modeling

Learn to convert real-world issues into mathematical language and model linear functions for various scenarios like cost, revenue, and depreciation.

katelyns
Download Presentation

Real-World Problems in Mathematics: Linear Functions & Modeling

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Section 1.3 Linear Functions and Mathematical Modeling

  2. Mathematical Modeling Formulating real world problems into the language of mathematics. Ex. The monthly payment, M, necessary to repay a home loan of P dollars, at a rate of r % per year (compounded monthly), for t years, can be found using

  3. Function A rule that assigns to each value of x one and only one value of y. is a function. Ex. We write f (x) , read “f of x”, in place of y to show the dependency of y on x . So and NOTE: It is notf times x

  4. Linear Function A linear function can be expressed in the form m and b are constants • Can be used for • Simple Depreciation • Linear Supply and Demand Functions • Linear Cost, Revenue, and Profit Functions

  5. Simple Depreciation Ex. A computer with original value $2000 is linearly depreciated to a value of $200 after 4 years. Find an equation for the value, V, of the computer at the end of year t.

  6. Cost, Revenue, and Profit Functions Ex. A shirt producer has a fixed monthly cost of $3600. If each shirt has a cost of $3 and sells for $12 find: a. The cost function Cost: C(x) = 3x + 3600 where x is the number of shirts produced. b. The revenue function Revenue: R(x) = 12x where x is the number of shirts sold. c. The profit from 900 shirts Profit: P(x) = Revenue – Cost = 12x – (3x + 3600) = 9x – 3600 P(900) = 9(900) – 3600 = $4500

  7. Linear Demand Ex. The quantity demanded of a particular game is 5000 games when the unit price is $6. At $10 per unit the quantity demanded drops to 3400 games. Find a demand equation relating the price p, and the quantity demanded, x (in units of 100).

More Related