1 / 55

Math 104 - Calculus I

Math 104 - Calculus I. August 9 (but first, a quick review…). Series of positive terms. Convergence questions for series of positive terms are easiest to understand conceptually.

kellykevin
Download Presentation

Math 104 - Calculus I

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Math 104 - Calculus I August 9 (but first, a quick review…)

  2. Series of positive terms Convergence questions for series of positive terms are easiest to understand conceptually. Since all the terms a are assumed to be positive, the sequence of partial sums {S } must be an increasing sequence. So the least upper bound property discussed earlier comes into play -- either the sequence of partial sums has an upper bound or it doesn't. If the sequence of partial sums is bounded above, then it must converge and so will the series. If not, then the series diverges. That's it. n n

  3. Tests for convergence of series of positive terms: The upper bound observations give rise to several "tests" for convergence of series of positive terms. They all are based pretty much on common sense ways to show that the partial sums of the series being tested is bounded are all less than those of a series that is known to converge (or greater than those of a series that is known to diverge). The names of the tests we will discuss are...

  4. Tests... 1. The integral test 2. The comparison test 3. The ratio test 4. The limit comparison test (sometimes called the ratio comparison test) 5. The root test TODAY TODAY

  5. The integral test Since improper integrals of the form provide us with many examples of telescoping series whose convergence is readily determined, we can use integrals to determine convergence of series:

  6. Integral test cont. For example, consider the series From the following picture, it is evident that the nth partial sum of this series is less than

  7. What is the sum? The sum of the terms is equal to the sum of the areas of the shaded rectangles, and if we start integrating at 1 instead of 0, the improper integral converges (question: what is the integral? so what bound to you conclude for the series?). Since the value of the improper integral (plus 1) provides us with an upper bound for all of the partial sums, the series must converge. It is an interesting question as to exactly what the sum is. We will answer it next week.

  8. The integral test...

  9. Discussion and Connect Question… -- for which exponents p does the series converge? (These are sometimes called p-series, for obvious reasons -- these together with the geometric series give us lots of useful examples of series whose convergence or divergence we know).

  10. Error estimates: Using the picture that proves the integral test for convergent series, we can get an estimate on how far off we are from the limit of the series if we stop adding after N terms for any finite value of N. If we approximate the convergent series by the partial sum then the error we commit is less than the value of the integral

  11. Take a closer look...

  12. Question A) Converge B) Diverge

  13. Question A) Converge B) Diverge

  14. Connect Exercise For this latter series, find a bound on the error if we use the sum of the first 100 terms to approximate the limit. (answer: it is less than about .015657444)

  15. The comparison test This convergence test is even more common- sensical than the integral test. It says that if all the terms of the series are less than the corresponding terms of the series and if converges, then converges also.

  16. Reverse This test can also be used in reversed -- if the b series diverges and the a’s are bigger than the corresponding b’s, then diverges also.

  17. Examples:

  18. Question A) Converge B) Diverge

  19. Question A) Converge B) Diverge

  20. Convergence Tests... 1. The integral test 2. The comparison test 3. The ratio test 4. The limit comparison test (sometimes called the ratio comparison test) 5. The root test

  21. The ratio test The ratio test is a specific form of the comparison test, where the comparison series is a geometric series. We begin with the observation that for geometric series, the ratio of consecutive terms is a constant (we called it r earlier).

  22. Ratio test (cont.) • For other series, even if the ratio of consecutive terms is not constant, it might have a limit as n goes to infinity. If this is the case, and the limit is not equal to 1, then the series converges or diverges according to whether the geometric series with the same ratio does. In other words:

  23. The ratio test:

  24. Example:

  25. Another example: For , the ratio is 1 and the ratio test is inconclusive. Of course, the integral test applies to these p-series.

  26. Question A) Converge B) Diverge

  27. Question A) Converge B) Diverge

  28. Root test • The last test for series with positive terms that we have to worry about is the root test. This is another comparison with the geometric series. It's like the ratio test, except that it begins with the observation that for geometric series, the nth root of the nth term approaches the ratio r as n goes to infinity (because the nth term is arnand so the nth root of the nth term is a1/nr-- which approaches r since the nth root of any positive number approaches 1 as n goes to infinity.

  29. The root test says...

  30. Example

  31. Question A) Converge B) Diverge

  32. Series whose terms are not all positive • Now that we have series of positive terms under control, we turn to series whose terms can change sign. • Since subtraction tends to provide cancellation which should "help" the series converge, we begin with the following observation: • A series with + and - signs will definitely converge if the corresponding series obtained by replacing all the - signs by + signs converges.

  33. Absolutely convergent series A series whose series of absolute values converges, which is itself then convergent, is called an absolutely convergent series.

  34. Examples... Series that are convergent although their series of absolute values diverge (convergent but not absolutely convergent) are called conditionally convergent.

  35. Alternating series A special case of series whose terms are of both signs that arises surprisingly often is that of alternating series . These are series whose terms alternate in sign. There is a surprisingly simple convergence test that works for many of these:

  36. Alternating series test:

  37. Example: The alternating harmonic series clearly satisfies the conditions of the test and is therefore convergent. The error estimate tells us that the sum is less than the limit, and within 1/5. Just to practice using the jargon, the alternating harmonic series, being convergent but not absolutely convergent, is an example of a conditionally convergent series.

  38. Classify each of the following... A) Absolutely convergent B) Conditionally divergent C) Divergent

  39. Classify each of the following... A) Absolutely convergent B) Conditionally divergent C) Divergent

  40. Classify each of the following... A) Absolutely convergent B) Conditionally divergent C) Divergent

  41. Power series Last week's project was to try and sum series using your calculator or computer. The answers correct to ten decimal places are: Sum((-1)^n/(2*n+1),n=0..infinity) = evalf(sum((-1)^n/(2*n+1),n=0.. infinity)); Sum(1/factorial(n),n=0..infinity)=evalf(sum(1/factorial(n),n=0..infinity));

  42. Power series (cont.) Sum(1/n^2,n=1..infinity)=evalf(sum(1/n^2,n=1..infinity)); Sum((-1)^(n+1)/n,n=1..infinity)=evalf(sum((-1)^ (n+1)/n,n=1..infinity)); We can recognize these numbers as

  43. Two directions: 1. Given a number, come up with a series that has the number as its sum, so we can use it to get approximations. 2. Develop an extensive vocabulary of "known" series, so we can recognize "familiar" series more often.

  44. Geometric series revisited

  45. r as a variable Changing our point of view for a minute (or a week, or a lifetime), let's think of r as a variable. We change its name to x to emphasize the point: So the series defines a function(at least for certain values of x).

  46. Watch out... We can identify the geometric series when we see it, we can calculate the function it represents and go back and forth between function values and specific series. We must be careful, though, to avoid substituting values of x that are not allowed, lest we get nonsensical statements like

  47. Power series If you look at the geometric series as a function, it looks rather like a polynomial, but of infinite degree. Polynomials are important in mathematics for many reasons among which are: 1. Simplicity -- they are easy to express, to add, subtract, multiply, and occasionally divide 2. Closure -- they stay polynomials when they are added, subtracted and multiplied. 3. Calculus -- they stay polynomials when they are differentiated or integrated

  48. Infinite polynomials So, we'll think of power series as "infinite polynomials", and write

  49. Three (or 4) questions arise... 1. Given a function (other than ), can it be expressed as a powerseries? If so, how? 2. For what values of x is a power series representation valid? (This is a two part question -- if we start with a function f(x) and form "its" power series, then (a) For which values of x does the series converge? (b) For which values of x does the series converge to f(x)? [There's also the question of "how fast".]

  50. continued 3. Given a series, can we tell what function it came from? 4. What is all this good for? As it turns out, the questions in order of difficulty, are 1, 2(a), 2(b) and 3. So we start with question 1:

More Related