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Section 19.2 Assessment

Section 19.2 Assessment. 12. An acid is highly ionized in aqueous solution. Is the acid strong or weak? Explain your reasoning. Section 19.2 Assessment. 13. How is the strength of a weak acid related to the strength of its conjugate base?. Section 19.2 Assessment.

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Section 19.2 Assessment

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  1. Section 19.2 Assessment 12. An acid is highly ionized in aqueous solution. Is the acid strong or weak? Explain your reasoning.

  2. Section 19.2 Assessment 13. How is the strength of a weak acid related to the strength of its conjugate base?

  3. Section 19.2 Assessment 14. Identify the acid-base pairs:

  4. Section 19.2 Assessment 14. Identify the acid-base pairs: HCOOH + H2O ↔ HCOO- + H3O+

  5. Section 19.2 Assessment 14. Identify the acid-base pairs: HCOOH + H2O ↔ HCOO- + H3O+

  6. Section 19.2 Assessment 14. Identify the acid-base pairs: NH3 + H2O ↔ NH4+ + OH-

  7. Section 19.2 Assessment 14. Identify the acid-base pairs: NH3 + H2O ↔ NH4++ OH-

  8. Section 19.2 Assessment 15. Kb for aniline is 4.3 x 10-10. Explain what this tells you about aniline.

  9. Section 19.2 Assessment [HX+ ][OH-] Kb = ------------------- [X]

  10. Section 19.2 Assessment [HX+ ][OH-] 4.3 x 10-10 = ------------------- [X]

  11. Section 19.2 Assessment [HX+ ][OH-] 4.3 x 10-10 = ------------------- [X] This number is very small

  12. Section 19.2 Assessment [HX+ ][OH-] 4.3 x 10-10 = ------------------- [X] This number is very small. Very little of X has been able to grab any H+

  13. Section 19.2 Assessment [HX+ ][OH-] 4.3 x 10-10 = ------------------- [X] This number is very small. Very little of X has been able to grab any H+. It is a weak base.

  14. Section 19.2 Assessment [HX+ ][OH-] 4.3 x 10-10 = ------------------- [X] This number is very small. Very little of X has been able to grab any H+. It is a weak base.

  15. Section 19.2 Assessment 16. Why is a strong base such as sodium hydroxide generally not considered to have a conjugate acid?

  16. Section 19.2 Assessment 16. Why is a strong base such as sodium hydroxide generally not considered to have a conjugate acid? NaOH ↔ Na+ + OH-

  17. Section 19.2 Assessment 16. Why is a strong base such as sodium hydroxide generally not considered to have a conjugate acid? NaOH ↔ Na+ + OH- It dissociates completely. NaOH → Na+ + OH-

  18. Section 19.2 Assessment 17. Which 0.1 M solution would have the greater electrical conductivity? HCLO Ka = 4.0 x 10-8 HF Ka = 6.3 x 10-4

  19. Section 19.2 Assessment Bigger Ka = stronger acid = more H+ ions in solution = more electrical conductivity HCLO Ka = 4.0 x 10-8 HF Ka = 6.3 x 10-4

  20. Section 19.2 Assessment Bigger Ka = stronger acid = more H+ ions in solution = more electrical conductivity HCLO Ka = 4.0 x 10-8 HF Ka = 6.3 x 10-4

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