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NEWMAR 115 – 12 – 20AU Full-Wave Rectifier with Choke-Input Filter

NEWMAR 115 – 12 – 20AU Full-Wave Rectifier with Choke-Input Filter. Choke-Input Filter. DC Operation. +. +. V dc. V ’ dc. -. -. V’ dc = V dc (R inductor ) / (R inductor + R load ). AC Operation (approximate). Normally, make X capacitor << R load. Approximate the Circuit. +.

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NEWMAR 115 – 12 – 20AU Full-Wave Rectifier with Choke-Input Filter

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  1. NEWMAR 115 – 12 – 20AUFull-Wave Rectifier with Choke-Input Filter ECE 442 Power Electronics

  2. Choke-Input Filter ECE 442 Power Electronics

  3. DC Operation + + Vdc V’dc - - V’dc = Vdc(Rinductor) / (Rinductor + Rload) ECE 442 Power Electronics

  4. AC Operation (approximate) Normally, make Xcapacitor << Rload ECE 442 Power Electronics

  5. Approximate the Circuit + + Vr V’r - - Usually, Xinductor >> Xcapacitor V’[rms] = (Xcapacitor / Xinductor)(Vr[rms]) ECE 442 Power Electronics

  6. Full-Wave Rectifier OutputOutput frequency = twice the line frequency Second Harmonic (first ac component) ECE 442 Power Electronics

  7. 2π(120) ECE 442 Power Electronics

  8. “Critical” Inductance, Lc Must keep the load current flowing for the complete cycle of the input voltage The dc load current must be > the peak value of the ac component of the load current ECE 442 Power Electronics

  9. Minimum Inductance Lc ECE 442 Power Electronics

  10. “Bleeder” Resistor • The bleeder resistor provides 2 functions • keeps a minimum current flowing through the inductor • discharges the filter capacitor after turn-off • Rbleeder = R1 = the largest value of Rload • sets the maximum value of inductor L ECE 442 Power Electronics

  11. Range of values for the Filter Choke • NEWMAR 115 – 12 – 20AU Power Supply • Lmax > R1/1000 = 5/1000 = 5mH  50mH • Lc >= R1/1000 = (12 V/20 A)/1000 = 0.6mH ECE 442 Power Electronics

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