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Check it out!

Check it out!. Cecilia took her first parachute jump lesson last weekend . Her instructor gave her the graph to the right that shows her change in altitude in meters during a 5-second interval. Use the graph to answer the questions that follow. . Altitude (meters). Time (seconds).

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Check it out!

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  1. Check it out! 3.5.1: Comparing Linear Functions

  2. Cecilia took her first parachute jump lesson last weekend. Her instructor gave her the graph to the right that shows her change in altitude in meters during a 5-second interval. Use the graph to answer the questions that follow. Altitude (meters) Time (seconds) 3.5.1: Comparing Linear Functions

  3. Estimate Cecilia’s average rate of change in altitude in meters per second. What are the domain and range for this function? 3.5.1: Comparing Linear Functions

  4. Estimate Cecilia’s average rate of change in altitude in meters per second. Select two points from the graph and use the slope formula to calculate the rate of change. Let (x1, y1) = (1, 2400) and (x2, y2) = (3, 1800). 3.5.1: Comparing Linear Functions

  5. Slope formula Substitute (1, 2400) and (3, 1800) for (x1, y1) and (x2, y2). Simplify as needed. The average rate of change is –300 meters per second. Cecilia’s altitude is decreasing an average of 300 meters each second. 3.5.1: Comparing Linear Functions

  6. What are the domain and range for this function? The domain is all possible x-values. In this problem, the domain is all real numbers greater than or equal to 0, or x ≥ 0. The range is all possible y-values. In this problem, the range is all real numbers greater than or equal to 0, but less than or equal to 2,700. This can be written symbolically as 0 ≤ y ≤ 2700 or as y ≥ 0 and y ≤ 2700. 3.5.1: Comparing Linear Functions

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