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SYSTEMS of EQUATIONS WORD PROBLEMS. A farmer grows only pumpkins and corn on her 420-acre farm. This year she wants to plant 250 more acres of corn than pumpkins. How many acres of each crop should the farmer plant?. Let x = pumpkins Let y = corn
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SYSTEMS of EQUATIONS WORD PROBLEMS
A farmer grows only pumpkins and corn on her 420-acre farm. This year she wants to plant 250 more acres of corn than pumpkins. How many acres of each crop should the farmer plant? • Let x = pumpkins • Let y = corn • Group acres with acres and crops with crops
x + y = 420 The number of acres for pumpkins and the acres for corn x + 250 = y There are 250 more acres of corn than there are pumpkins x+ x + 250 = 420 substitute x + 250 for y in the first equation 2x + 250 = 420 Combine like terms 2x = 170 Subtract 250 from both sides x = 85 There are 85 acres of pumpkins 420 – 85 There are 335 acres of corn
A perfume maker has stocks of two perfumes on hand. Perfume A sells for $15 per ounce. Perfume B sells for $35 per ounce. How much of each should be combined to make a 3-oz bottle of perfume that can be sold for $63.
A + B = 3 Ounces of each bottle of perfume $15A + $35B = $63 The prices of each bottle to make the new bottle A = 3 – B Isolate one of the values 15(3-B) + 35B = 63 Substitute the value of A for A 45 – 15B + 35B = 63 Distribute the 15 45 + 20B =63 Combine like terms 20B = 18 Subtract 45 from both sides B = .9 Divide both sides by 20 A + .9 = 3 Substitute .9 for B A = 2.1 Subtract .9 from both sides Final Answer 2.1 of Perfume A .9 of Perfume B