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Forensics and CS. Philip Chan. CSI: Crime Scene Investigation. www.cbs.com/shows/ csi / high tech forensics tools DNA profiling Use as evidence in court cases. DNA. Deoxyribonucleic Acid Each person is unique in DNA (except for twins) DNA samples can be collected at crime scenes
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Forensics and CS Philip Chan
CSI: Crime Scene Investigation • www.cbs.com/shows/csi/ • high tech forensics tools • DNA profiling • Use as evidence in court cases
DNA • Deoxyribonucleic Acid • Each person is unique in DNA (except for twins) • DNA samples can be collected at crime scenes • About .1% of human DNA varies from person to person
Forensics Analysis • Focus on loci (locations) of the DNA • Values at the those loci (DNA profile) are recorded for comparing DNA samples. • Two DNA profiles from the same person have matching values at all loci. • More or fewer loci are more accurate in identification? • Tradeoffs? • FBI uses 13 core loci • http://www.cstl.nist.gov/biotech/strbase/fbicore.htm
We do not want to wrongly accuse someone • How can we find out how likely another person has the same DNA profile? • How many people are in the world? • How low the probability needs to be so that a DNA profile is unique in the world? • Low probability doesn’t mean impossible • Just very unlikely
Review of basic probability • Joint probability of two independent events • P(A,B) = ?
Review of basic probability • Joint probability of two independent events • P(A,B) = P(A) * P(B) • Independent events mean knowing one event does not provide information about the other events • P(Die1=1, Die2=1) • = P(Die1=1) * P(Die2=1) • = 1/6 * 1/6 = 1/36.
Enumerating the events 36 events, each is equally likely, so 1/36
Joint probability • P(Die1=even, Die2=6) = ?
Joint probability • P(Die1=even, Die2=6) • = 1/2 * 1/6 = 1/12 • P(Die1=1, Die2=5, Die3=4) = ?
Joint probability • P(Die1=even, Die2=6) • = 1/2 * 1/6 = 1/12 • P(Die1=1, Die2=5, Die3=4) • = (1/6)3 = 1/216
DNA profile probability • How to estimate?
DNA profile probability • How to estimate? • Assuming loci are independent • P(Locus1=value1, Locus2=value2, ...) • = P(Locus1=value1) * P(Locus2=value2) * ...
DNA profile probability • How to estimate? • Assuming loci are independent • P(Locus1=value1, Locus2=value2, ...) • = P(Locus1=value1) * P(Locus2=value2) * ... • How to estimate P(Locus1=value1)?
DNA profile probability • How to estimate? • Assuming loci are independent • P(Locus1=value1, Locus2=value2, ...) • = P(Locus1=value1) * P(Locus2=value2) * ... • How to estimate P(Locus1=value1)? • a random sample of size N from the population and • find out how many people out of N have value1 at Locus1
Problem Formulation • Given • A sample profile (e.g. collected from the crime scene) • A database of known profiles • Find • The probability of the sample profile if it matches a known profile in the database
Breaking Down the Problem • Find • The probability of the sample profile if it matches a known profile in the database • What are the subproblems?
Breaking Down the Problem • Find • The probability of the sample profile if it matches a known profile in the database • What are the subproblems? • Subproblem 1 • Find whether the sample profile matches • 1a: ? • 1b: ? • Subproblem 2 • Calculate the probability of the profile
Breaking Down the Problem • Find • The probability of the sample profile if it matches a known profile in the database • What are the subproblems? • Subproblem 1 • Find whether the sample profile matches • 1a: check entries in the database • 1b: check if all 13 loci match in each entry • Subproblem 2 • Calculate the probability of the profile
Simpler Problem for 1a (very common) • Given • an array of integers (e.g. student IDs) • an integer (e.g. an ID) • Find • whether the integer is in the array int[] directory; // student id’s int id; // to be found boolean found; // true if id is in directory
Linear/Sequential Search • Check one by one • Stop if you find it • Stop if you run out of items to check • Not found
Number of Checks (speed of algorithm) • Consider N items in the array • Best-case scenario • When does it occur? How many checks?
Number of Checks (speed of algorithm) • Consider N items in the array • Best-case scenario • When does it occur? How many checks? • First item;1 check • Worst-case scenario • When does it occur? How many checks?
Number of Checks (speed of algorithm) • Consider N items in the array • Best-case scenario • When does it occur? How many checks? • First item;1 check • Worst-case scenario • When does it occur? How many checks? • Last item or not there; N checks • Average-case scenario • Average of all cases • (1 + 2 + … + N) / N =
Can we do better? Faster algorithm? • What if the array is sorted, items are in an order • E.g. a phone book
Binary Search • Check the item at midpoint • If found, done • Otherwise, eliminate half and repeat
Breaking down the problem • While more items and not found • What are the two subproblems?
Breaking down the problem • While more items and not found • Eliminate half of the items • Find the mid point
Number of checks (Speed of algorithm) • Best-case scenario • When does it occur? How many checks?
Number of checks (Speed of algorithm) • Best-case scenario • When does it occur? How many checks? • In the middle; 1 check
Number of checks (Speed of algorithm) • Best-case scenario • When does it occur? How many checks? • In the middle; 1 check • Worst-case scenario • When does it occur? How many checks?
Number of checks (Speed of algorithm) • Best-case scenario • When does it occur? How many checks? • In the middle; 1 check • Worst-case scenario • When does it occur? How many checks? • Dividing into two halves, half has only one item • ? checks
Number of checks (Speed of algorithm) • Best-case scenario • When does it occur? How many checks? • In the middle; 1 check • Worst-case scenario • When does it occur? How many checks? • Dividing into two halves, half has only one item • ? checks
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1 = [ T(N/4) + 1 ] + 1
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1 = [ T(N/4) + 1 ] + 1
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1 = [ T(N/4) + 1 ] + 1 = [ [ T(N/8) + 1] + 1] + 1
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1 = [ T(N/4) + 1 ] + 1 = [ [ T(N/8) + 1] + 1] + 1 = … any pattern?
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1 = [ T(N/4) + 1 ] + 1 = [ [ T(N/8) + 1] + 1] + 1 = … = T(N/2k) + k
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1 = [ T(N/4) + 1 ] + 1 = [ [ T(N/8) + 1] + 1] + 1 = … = T(N/2k) + k N/2k gets smaller and eventually becomes 1
Number of checks (Speed of algorithm) T(1) = 1 T(N) = T(N/2) + 1 = [ T(N/4) + 1 ] + 1 = [ [ T(N/8) + 1] + 1] + 1 = … = T(N/2k) + k • N/2k gets smaller and eventually becomes 1 • solve for k
Number of Checks (Speed of Algorithm) • N/2k = 1 N = 2k k = ?
Number of Checks (Speed of Algorithm) • N/2k = 1 N = 2k k = log2N
Number of Checks (Speed of Algorithm) • N/2k = 1 N = 2k k = log2N • T(N) = T(N/2k) + k = T(1) + log2N = ? + log2N
Number of Checks (Speed of Algorithm) • N/2k = 1 N = 2k k = log2N • T(N) = T(N/2k) + k = T(1) + log2N = 1 + log2N
Sorting (arranging the items in adesired order) • How is the phone book arranged? • Why? • Why not arranged by numbers?
Sorting (arranging the items in adesired order) • How is the phone book arranged? • Why? • Why not arranged by numbers? • Order • Alphabetical • Low to high numbers • DNA profile with 13 loci?
Sorting • Imagine you have a thousand numbers in an array • How would you systemically sort them?