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The Breakpoint Graph. 1 5- 2- 4 3 . The Breakpoint Graph. 6 1 5- 2- 4 3 0. Augment with 0 = n+1. The Breakpoint Graph.
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The Breakpoint Graph 1 5- 2- 4 3
The Breakpoint Graph 6 1 5- 2- 4 3 0 • Augment with 0 = n+1
The Breakpoint Graph 11 2 1 9 10 3 4 8 7 6 5 0 6 1 5- 2- 4 3 0 • Augment with 0 = n+1 • Vertices 2i, 2i-1 for each i
The Breakpoint Graph 11 2 1 9 10 3 4 8 7 6 5 0 6 1 5- 2- 4 3 0 • Augment with 0 = n+1 • Vertices 2i, 2i-1 for each i • Blue edges between adjacent vertices
The Breakpoint Graph 11 2 1 9 10 3 4 8 7 6 5 0 6 1 5- 2- 4 3 0 • Augment with 0 = n+1 • Vertices 2i, 2i-1 for each i • Blue edges between adjacent vertices • Red edges between consecutive labels 2i,2i+1
Sort a given breakpoint graph 11 2 1 9 10 3 4 8 7 6 5 0 into n+1 trivial cycles 11 10 9 8 7 6 5 4 3 2 1 0
Sort a given breakpoint graph 11 2 1 9 10 3 4 8 7 6 5 0 into n+1 trivial cycles 11 10 9 8 7 6 5 4 3 2 1 0 Conclusion:We want to increase number of cycles
Def:A reversal acts on two blue edges 11 2 1 9 10 3 4 8 7 6 5 0 cutting them and re-connecting them 11 2 1 9 10 3 4 7 8 6 5 0
A reversal can either 11 2 1 9 10 3 4 8 7 6 5 0 Act on two cycles, joining them (bad!!) 11 2 1 9 10 3 4 7 8 6 5 0
A reversal can either 11 2 1 9 10 3 4 8 7 6 5 0 Act on one cycle, changing it (profitless) 11 2 1 5 6 7 8 4 3 10 9 0
A reversal can either 11 2 1 9 10 3 4 8 7 6 5 0 Act on one cycle, splitting it (good move) 11 10 9 1 2 3 4 8 7 6 5 0
Basic Theorem (Bafna, Pevzner 93) Where d=#reversals needed (reversal distance), and c=#cycles. Proof: Every reversal changes c by at most 1.
Basic Theorem (Bafna, Pevzner 93) Where d=#reversals needed (reversal distance), and c=#cycles. Proof: Every reversal changes c by at most 1. Alternative formulation: where b=#breakpoints, and c ignores short cycles
Oriented Edges Red edges can be : Oriented{ Right-to-Right Left-to-Left Unoriented{ Left-to-Right Right-to-Left
Oriented Edges Red edges can be : Oriented{ Right-to-Right Left-to-Left Unoriented{ Left-to-Right Right-to-Left Def:This reversal acts on the red edge
Oriented Edges Red edges can be : Oriented{ Right-to-Right Left-to-Left Unoriented{ Left-to-Right Right-to-Left Def:This reversal acts on the red edge Thm: A reversal acting on a red edge is good the edge is oriented
Overlapping Edges Def: Two red edges are said to be overlapping if they span intersecting intervals which do not contain one another.
Overlapping Edges Def: Two red edges are said to be overlapping if they span intersecting intervals which do not contain one another The lines intersect
Overlapping Edges Def: Two red edges are said to be overlapping if they span intersecting intervals which do not contain one another The lines intersect Thm: A reversal acting on a red edge flips the orientation of all edges overlapping it, leaving other orientations unchanged
Overlapping Edges Def: Two red edges are said to be overlapping if they span intersecting intervals which do not contain one another The lines intersect Thm: if e,f,g overlap each other, then after applying a reversal that acts on e,f and g do not overlap
Overlap Graph Nodes correspond to red edges. Two nodes are connected by an arc if they overlap
Overlap Graph Nodes correspond to red edges. Two nodes are connected by an arc if they overlap Def:Unoriented connected components in the overlap graph - all nodes correspond to oriented edges.
Overlap Graph Nodes correspond to red edges. Two nodes are connected by an arc if they overlap Def:Unoriented connected components in the overlap graph - all nodes correspond to oriented edges. Cannot be solved in only good moves
Dealing with Unoriented Components • A profitless move on an oriented edge, making its component to oriented
Dealing with Unoriented Components • A profitless move on an oriented edge, making its component to oriented or: • A bad move (reversal) joining cycles from different unoriented components, thus merging them flipping the orientation of many components on the way
Hurdles • Def:Hurdle - an unoriented connected component which is consecutive along the cycle
Hurdles • Def:Hurdle - an unoriented connected component which is consecutive along the cycle • Thm: (Hannenhalli, Pevzner 95) Proof: A hurdle is destroyed by a profitless move, or at most two are destroyed (merged) by a bad move.
Hurdles • Def:Hurdle - an unoriented connected component which is consecutive along the cycle • Thm: (Hannenhalli, Pevzner 95) Proof: A hurdle is destroyed by a profitless move, or at most two are destroyed (merged) by a bad move. • Thm: