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Colligative Properties. Test Chapter 15 Tuesday May 7, 2002. Colligative Properties. Colligative Properties are those properties of a liquid that may be altered by the presence of a solute. Examples of these properties are: the vapor pressure the freezing and boiling points and
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Colligative Properties Test Chapter 15 Tuesday May 7, 2002
Colligative Properties • Colligative Properties are those properties of a liquid that may be altered by the presence of a solute. • Examples of these properties are: • the vapor pressure • the freezing and boiling points and • the osmotic pressure. • All of these properties ultimately relate to the vapor pressure.
Raoult’s Law Psolvent = Xsolvent Posolvent Pure solvent Mole fraction Solution
Boiling Point Elevation • Pure water boils at 100ºC • A solution of water and sucrose boils at MORE than 100 ºC • The more sucrose we add the HIGHER the boiling point.
Freezing Point Depression • Pure water freezes at 0ºC • A solution of water and sucrose freezes at LESS than 0ºC • The more sucrose we add the LOWER the freezing point.
Impurities in a substance cause a change in its phase diagram by making the liquid region bigger The addition of solute RAISES the boiling point and LOWERS the freezing point of a solvent.
MOLALITY • Molarity (M) number of moles per liter of solution • MOLALITY (m) number of moles per kilogram of solvent. number of moles m = ---------------------------------- mass of solvent (kg)
Molality: Problem 1 • You pour 12 g of KBr into a beaker that contains 600 mL of water. What will be the molality of the resulting solution? MKBr = 39.098 + 79.904 = 119.002 g n = 12/119.002 = 0.10084 mol KBr mass (H2O) = 600 mL = 600 g = 0.60 kg m = 0.10084 mol / 0.60 kg = 0.168 m
Molality: Problem 2 • How many grams of MgF2 would you need to prepare a 0.75m solution of MgF2 using 220g of water? MMgF2 = 24.305 + 2 x 18.996 = 62.297 g mass of Mg = 0.75m x 0.220kg x 62.297 g = 10.2790 g
Colligative Properties: Computations • Boiling Point elevation: ΔTb = ٭ kb m Molality Coefficient of BP elevation Number of particles Change in BP (ºC) • etiin
Colligative Properties: Computations • Freezing Point depression: ΔTf = ٭ kf m Molality Coefficient of FP depression Number of particles Change in FP (ºC) • etiin
Number of particles in solution • When sucrose is dissolved in water, the molecules remain as one particle. C12H24O12(s) C12H24O12(aq) • When sodium chloride is dissolved in water, it dissociates into 2 particles: NaCl(s) Na+(aq) + Cl– (aq) • When calcium chloride is dissolved in water, it dissociates into 3 particles CaCl2(s) Ca+ + 2 Cl–(aq) • NaCl and CaCl2 are called electrolytes because their solution conduct electricity.
The larger the number of particles released by a solute the greater its effect on the BP and FP. • So we would expect: • NaCl to be twice as effective as sucrose • CaCl2 to be thrice as effective as sucrose • The size of the particles is unimportant • In real life ionic compounds do not dissociate completely
OSMOSIS is the movement of solvent through a membrane to equalize the concentration on both sides.