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Open Day 26 - 27 luglio 2013

Open Day 26 - 27 luglio 2013. IDEA Creator Experimental Creative Culture. Classic Situation. 3. The engine power is spread over the different-diameter pulleys. F3. Rad/s. F2. 2. F1. F x b x Rad/s. C. 1. F4. 4. Transmission belt. d/ i. d. LEVA. F. F’. D. .

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Open Day 26 - 27 luglio 2013

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  1. Open Day 26 - 27 luglio 2013 IDEA Creator Experimental Creative Culture

  2. Classic Situation 3 The engine power is spread over the different-diameter pulleys F3 Rad/s F2 2 F1 F x b x Rad/s C 1 F4 4 Transmission belt

  3. d/ i d LEVA F F’ D  Classic lever C’ C  F’ = F x i P = P’ LEVA F D  Rpm b/i Rpm b TURBINA CCS  F’ Double lever F’ = F x i2 P’ = Fxi2 x b/i x rpm = P x i

  4. Classic situation ALTERNATOR ENGINE Here is an alternator put together directly with the engine; in this case the engine power is equal to the alternator power. This situation is the same as the CLASSIC situation ENGINE Improved turbine CCS A B To me this situation is not the same as the previous one; here the power arm of the engine is introduced (AC), which is reduced on the alternator (A’C), obtaining on this one an improved power. SHAFT movement FULCRUM C ALTERNATOR B’ A’

  5. F B M A F’ F  P’ P D/i D R’ R WO/2005/047695 1 RM A F RM’ M B F’ F P’ P D/i D EP 2489875 R’ R

  6. A F’ RM RM’ P’ M B Frizione (friction) F  P D F R EP 2489875

  7. ……where as opposed to the “classic situation” the power moment is introduced compared to the fulcrum C Turning engine Fixed wheel(1) D The engine and the alternator are not fixed but they turn around The fixed wheel : in one second the engine goes from A to D and the alternator from B to D’ A C Engine power = Alternator power B F x b x rad/s x AC = F’ x b’ x rad’/s x CB when AC=CB The shaft hooks the engine And the alternator, plus it pivots on C D’ Turning alternator

  8. Turning engine on Fixed wheel1) Fixed wheel on which The engine pivots (1) B A Engine power < Alternator power Fixed wheel on which The alternator pivots (2) C A’ Let’s suppose that AC/A’C = 2 and let’s balance the Power moments compared to the fulcrum C Engine Power Alternator Power F x b x rad/s x AC = F’ x b’ x rad’/s x A’C F x b x rad/s x AC = F’ x b’ x rad’/s x AC/2 Reducing I obtain that the alternator power is the same as: F’ x b’ x rad’/s = 2 x F x b x rad/s On the red fixed wheel a power is discharged; this is equal to: Engine power x AC/ (AC/2) = Engine power x 2 B’ Turning alternator which engaged In the red fixed wheel The shaft hooks the engine And the alternator, plus it pivots on C

  9. Transferred mass because of the transformation Of the mechanical energy to kinetic energy Fixed wheel on which the engine pivots (1) and concentric wheel on which the engine is set (1’); the engine turns and Spreads the motion to the red Wheel (2) thanks to a wheel(1’’). The red wheel (2) spreads The motion to the alternator. Turning engine m x g x V F B A P engine => Kinetic Energy Mass=> P alternator F1 C m g V / ½ m V2 / s F2 m x g x V 2 Fixed alternator engages In the red wheel The Gear wheel Turns for the wheel (1’’)

  10. Fixed wheel on which the engine pivots (1) and concentric wheel on which the engine is set (1’); the engine turns and Spreads the motion to the red Wheel (2) thanks to a wheel(1’’). The red wheel (2) spreads The motion to the alternator. Turning engine m B A m’ ½ m V2 / s = ½ m’ V’2 / s m’ = m x i 2 C m’ Fixed alternator Connected with the red wheel m m x i 2 x g x V/i = alternator Power > engine Power

  11. CONVENIENCE DECISION B B A A m C C A’ B’ m Arrangement B Arrangement A If 2 g / V engine/ s > 1 the arrangement B is more convenient than A

  12. 1 A A 1 M AB AB M M M RM RM RM RM RP A A RM’ RM’ M M R R’ R RM RM Assetto 1

  13. AB 1 M RM’ RP 1 RM R M M RM RM R’ R A RM’ A Assetto 2

  14. M A AB 1 RP M M A RM RM’ R Assetto 3

  15. D/i D AB’ C/i   b/i   F’ R’ C F x b x rad/s x C x D = F’ x b’ x rad’/s x C/i x D/i P alternatore = P motore x i2 Spostamento angolare b   F R Assetto 4 AB

  16. D/i D AB’ C/i   b/i   F’ R’ C P alternatore = m x g x i3 x V/ i Spostamento angolare b   F R Assetto 5 AB

  17. b/i RM’ F’ Frizione D AB’   C P alternatore > P motore ed è funzione anche della componente C Spostamento angolare b   F R Assetto 6 AB

  18. Turbina perfezionata CCS

  19. motore riduttore alternatore Turbina perfezionata CCS

  20. Turbina perfezionata CCS Cultura Creativa Sperimentale Experimental Creative Culture Grazie per l’attenzione Alessandro Leghi

  21. HOW GREEN SOCIAL MONEY WORKS € circulates again Depending on the social green system employer/work Pays the employees in € 6 Bank CCS 7 1 2 Wage € € are transformed in vouchers in GREEN SOCIAL virtual money Euros are moltiplied for a value equal/greater than 1 Depending on the green social usefulness for which they are spent. The vouchers have a face validity, they have a due date and an end use They have an UEI value = € x green social coefficient >= 1 5 3 green social shopping With vouchers in UEI Buisnessmen pay the UEI off in CCS banks Transforming them in € to pay the production. Wages,green social services are paied and the “USEFUL” investment is rewarded. 4

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