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Section 6.1

Chapter 6. Section 6.1. Exercise #9. Determine which of the ordered pairs are solutions for the given equation. 3x  2y = 12. (0, 6),. (4, 0),. 3(4)  2(0) = 12. 12  0 = 12. true. (4, 0). 3( )  2( 5 ) = 12. (4, 0).

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Section 6.1

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  1. Chapter 6 Section 6.1 Exercise #9

  2. Determine which of the ordered pairs are solutions for the given equation. 3x  2y = 12 (0, 6), (4, 0), 3(4)  2(0) = 12 12  0 = 12 true (4, 0)

  3. 3( )  2(5) = 12 (4, 0) Determine which of the ordered pairs are solutions for the given equation. 3x  2y = 12 (0, 6), (4, 0), 2  (10) = 12 true

  4. (4, 0) Determine which of the ordered pairs are solutions for the given equation. 3x  2y = 12 (0, 6), (4, 0), 3(0)  2(6) = 12 0  12 = 12 Not true

  5. 3( 5)  2() = 12 (4, 0) Determine which of the ordered pairs are solutions for the given equation. 3x  2y = 12 (0, 6), (4, 0), 15  (3) = 12 true

  6. Chapter 6 Section 6.1 Exercise #21

  7. Complete the ordered pairs so that each is a solution for the given equation. 3x  2y = 12 (2, ), ( , 0), ( , 3 ) 4 ( , 6), 3x  2(0) = 12 3x  0 = 12 3x = 12 x = 4

  8. Complete the ordered pairs so that each is a solution for the given equation. 3x  2y = 12 (2, ), 4 ( , 0), ( , 3 ) 0 ( , 6), 3(x)  2(6) = 12 3(x) + 12 = 12 3x = 0 x = 0

  9. Complete the ordered pairs so that each is a solution for the given equation. 3x  2y = 12 (2, ), ( , 0), ( , 3 ) 4 0 ( , 6), 3 3(2)  2y = 12 6  2y = 12 2y = 6 y = 3

  10. Complete the ordered pairs so that each is a solution for the given equation. 3x  2y = 12 (2, ), ( , 0), ( , 3 ) 6 4 0 ( , 6), 3 3x  2(3) = 12 3x  6 = 12 3x = 18 x = 6

  11. Chapter 6 Section 6.1 Exercise #23

  12. ( , ) ( , ) –9 x = 3 Complete the ordered pairs so that each is a solution for the given equation. y = 3x + 9 ( , 0) (0, ) 3 0 = 3x + 9 –9 = 3x x = 3

  13. ( , ) ( , ) y = 3 ( ) + 9 Complete the ordered pairs so that each is a solution for the given equation. y = 3x + 9 ( , 0) (0, ) 11 3 y = 2 + 9 y = 11

  14. ( , ) ( , ) Complete the ordered pairs so that each is a solution for the given equation. y = 3x + 9 ( , 0) (0, ) 9 11 3 y = 3(0) + 9 y = 9

  15. ( , ) ( , ) y = 3 ( ) + 9 – Complete the ordered pairs so that each is a solution for the given equation. y = 3x + 9 ( , 0) (0, ) 9 7 11 3 y = – 2 + 9 y = 7

  16. Chapter 6 Section 6.1 Exercise #27

  17. Find four solutions for the following equation. x  y = 7 Solution with x = 0: 0  y = 7  y = 7 y = 7 (0, 7)

  18. Find four solutions for the following equation. x  y = 7 Solution with x = 2: 2  y = 7  y = 5 y = 5 (0, 7) (2, 5)

  19. Find four solutions for the following equation. x  y = 7 Solution with x = 4: 4  y = 7  y = 3 y = 3 (0, 7) (2, 5) (4, 3)

  20. Find four solutions for the following equation. x  y = 7 Solution with x = 6: 6  y = 7  y = 1 y = 1 (0, 7) (2, 5) (4, 3) (6, 1)

  21. Chapter 6 Section 6.1 Exercise #43

  22. An equation in three variables has an ordered triple as a solution. For example, (1, 2, 2) is a solution to the equation x + 2y – z = 3. Complete the ordered-triple solution for the following equation. 2x + y + z = 2 (–2, , 1) 5 2(–2) + y + (1) = 2 –4 + y + (1) = 2 –3 + y = 2 y = 5

  23. Chapter 6 Section 6.1 Exercise #49

  24. x 1 2 3 6 4 y Statistics. The number of programs for the disabled in the United States from 1993 to 1997 is approximated by the equation y = 162x + 4365 in which x is the number of years after 1993. Complete the following table. 4527 4689 4851 5013 5337

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