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Balancing Redox Reactions

Balancing Redox Reactions. Steps :. Assign oxidation numbers Write half reactions Balance electrons to determine coefficients needed. Problem 1:. +2 -2 0 0. 2HgO  O 2 + 2Hg. Hg +2 + 2e -  Hg 0. Reduction. O -2  O 0 + 2e -. Oxidation. Problem 2:.

lester-george
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Balancing Redox Reactions

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  1. Balancing Redox Reactions

  2. Steps: Assign oxidation numbers Write half reactions Balance electrons to determine coefficients needed

  3. Problem 1: +2 -2 0 0 2HgO  O2+ 2Hg Hg+2 + 2e- Hg0 Reduction O-2 O0 + 2e- Oxidation

  4. Problem 2: +1 +5 -2 +1 -1 0 2KClO3 2KCl + 3O2 6e- + Cl+5 Cl-1 Reduction 3(O-2 O0 + 2e-) Oxidation

  5. Problem 3: +1 -1 0 +2 -1 0 2HCl + Zn  ZnCl2 + H2 2e- + 2H+1 H20 Reduction Zn0 Zn+2 + 2e- Oxidation

  6. Problem 4: +1 +5 -2 0 +2 +5 -2 0 2Ag NO3 + Cu  Cu(NO3)2 + 2Ag 2e- + 2Ag+1 2Ag0 Reduction Cu0 Cu+2 + 2e- Oxidation

  7. Problem 5: -3 +1 0 0 +1 -2 4NH3 + 3O2  2N2 + 6H2O 12e- + 3O20 6O-2 Reduction 4N-3 2N20 + 12e- Oxidation

  8. Problem 6: 0 +3 +5 -2 0 +2 +5 -2 3Mg + 2Al(NO3)3 2Al + 3Mg(NO3)2 6e- + 2Al+3 2Al0 Reduction 3Mg0 3Mg+2 + 6e- Oxidation

  9. Problem 6: 0 +3 +2 0 3Ca + 2Al3+ 3Ca2+ + 2Al 6e- + 2Al+3 2Al0 Reduction 3Ca0 3Ca+2 + 6e- Oxidation

  10. Problem 7: 2Fe3+ + Sn2+ 2Fe2+ + Sn4+ 2e- + 2Fe+3 2Fe+2 Reduction Sn+2 Sn+4 + 2e- Oxidation

  11. Problem 8: +1 +5 -2 +2 -1 +1 -1 +2 -2 +4 -1 +1 -2 2HNO3 + 3MnCl2 + 6HCl  2NO + 3MnCl4 + 4H20 6e- + 2N+5 2N+2 Reduction 3Mn+2 3Mn+4 + 6e- Oxidation

  12. Problem 9: +1 +6 -2 +1 -1 0 +1 -2 +3 -1 +1 -1 K2(Cr2O7) + 14HCl  3Cl2 + 7H2O + 2CrCl3 + 2KCl 6e- + Cr2+6 2Cr+3 Reduction 6Cl-1 3Cl20 + 6e- Oxidation

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