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Balancing Redox

Balancing Redox. Half Reaction. Each redox reaction can be divided into two parts: one for oxidation, the other reduction These parts are called half-reactions Ex. – Break into two half-reactions Ce 4+ + Sn 2+  Ce 3+ + Sn 4+. Balancing Redox.

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Balancing Redox

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  1. Balancing Redox

  2. Half Reaction Each redox reaction can be divided into two parts: one for oxidation, the other reduction These parts are called half-reactions Ex. – Break into two half-reactions Ce4+ + Sn2+  Ce3+ + Sn4+

  3. Balancing Redox Atoms and charges must be balanced Balance the acidic redox reaction below H+ + Cl- + Sn + NO3- SnCl62- + NO2 + H2O

  4. Step 1 For Balancing Determine oxidation states for all atoms in the reaction -1 0 +5 -2 +4 -1 +4 -2 +1 -2 +1 H+ + Cl- + Sn + NO3- SnCl62- + NO2 + H2O

  5. Step 2 Show electrons gained and lost using “tie lines” 1 e- gained -1 0 +5 -2 +4 -1 +4 -2 +1 -2 +1 H+ + Cl- + Sn + NO3- SnCl62- + NO2 + H2O 4 e- lost

  6. Step 3 Use coefficients to equalize the electrons gained and lost -1 0 +5 -2 +4 -1 +4 -2 +1 -2 +1 H+ + Cl- + Sn + 4NO3- SnCl62- + 4NO2+ H2O

  7. Step 4 Balance the rest by inspection 8H+ + 6Cl- + Sn + 4NO3- SnCl62- + 4NO2+ 4H2O

  8. Sample Balance the redoxreaction below PbO + NH3→ N2 + H2O + Pb

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