1 / 3

Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m 2 x 3,5 m = 140 kg/m

Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m 2 x 3,5 m = 140 kg/m. q 2 x 1 cos  2 140 kg / m 2 x 1 m cos 30,9637 o. P angin = Pa2 =. =. = 163,26 kg. 1 4. M angin = Ma2 = =. x Pa2 x j x 163,26 kg x 3,5 m. 1 4. = 142,85 kgm

lexi
Download Presentation

Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m 2 x 3,5 m = 140 kg/m

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m2 x 3,5 m = 140 kg/m q2 x 1 cos 2 140 kg / m 2 x 1 m cos 30,9637 o P angin = Pa2 = = = 163,26 kg 1 4 M angin = Ma2 = = x Pa2 x j x 163,26 kg x 3,5 m 1 4 = 142,85 kgm 1 http://www.mercubuana.ac.id

  2. 25,67243,522 = 5 4 = 50,52 kg/cm2 < (lt x ) 5 4 50,52 kg/cm2 < ( 100 kg/cm2 x = ) = 50,52 kg/cm2 < 125 kg/cm2 ........................ (OK) 3,5 x 100 300 L 300 Lendutan ijin = = = 1,16 cm BENTUK 1 1) Beban mati : = 99,3 kg/m’ q bm q bm x = 99,3 kg/m x sin 54,4623o = 80,8 kg/m q bm y = 99,3 kg/m x cos 54,4623o = 57,72 kg/m 2) Beban angin: 40 kg / m 2 x 1 m cos 54,4623o 40 kg / m 0,5812 qa = = = 68,82 kg/m’ qax = 0 qay = 68,82 kg/m’ 3) Total beban terbagi rata: qx = q bmx + q ax = 80,8 kg/m + 0 = 80,8 kg/m qy = q bmy + q ay = 57,72 kg/m + 68,82 kg/m = 126,54 kg/m 3 http://www.mercubuana.ac.id

  3. q x L4 x x EI y P x L3 x x EI y 5 384 1 48 x = + 80,8 / 100 x 350 4 1 100.000 x x 20 x 12 3 12 81,37 x 350 3 1 100.000 x x 20 x 12 3 12 5 384 1 48 x x = + = 0,55 + 0,25 = 0,80 cm q y x L4 EI x Py x L3 EI x 5 384 1 48 y = x x + 126,54 / 100 x 350 4 1 100.000 x x 12 x 20 3 12 58,12 x 350 3 1 100.000 x x 12 x 20 3 12 5 384 1 48 x x = + = 0,31 + 0,06 = 0,37 cm x2y2 0,8020,372  = = = 0,88 cm < = 1,16 cm ....... (OK) Jadi gording dengan ukuran penampang 12/20 dapat dipakai LENDUTAN PADA GORDING () 3,5 x 100 300 L 300 Lendutan ijin = = = 1,16 cm BENTUK 2 1) Beban mati : = 99,3 kg/m’ q bm q bm x = 99,3 kg/m x sin 30,9637o = 51,08 kg/m q bm y = 99,3 kg/m x cos 30,9637o = 85,14 kg/m 2) Beban angin: 5 http://www.mercubuana.ac.id

More Related