1 / 20

2 minutes Bell Ringer 10-17 p. 50-51 1 , 3, 9 3 minutes

2 minutes Bell Ringer 10-17 p. 50-51 1 , 3, 9 3 minutes Then turn to p. 40 to Bisect an angle Follow steps 1-4 Use an entire sheet of paper in your notebook. Concept. Angle Measure.

lieu
Download Presentation

2 minutes Bell Ringer 10-17 p. 50-51 1 , 3, 9 3 minutes

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 2 minutes • Bell Ringer 10-17 • p. 50-51 1, 3, 9 3 minutes • Then turn to p. 40 to Bisect an angle • Follow steps 1-4 • Use an entire sheet of paper in your notebook

  2. Concept

  3. Angle Measure ALGEBRA Find the measures of two supplementary angles if the measure of one angle is 6 less than five times the measure of the other angle. UnderstandThe problem relates the measures of two supplementary angles. You know that the sum of the measures of supplementary angles is 180. Plan Draw two figures to represent the angles. Example 2

  4. Angle Measure Solve 6x – 6 = 180 Simplify. 6x = 186 Add 6 to each side. x = 31 Divide each side by 6. Example 2

  5. Angle Measure Use the value of x to find each angle measure. mA = x mB = 5x – 6 = 31 = 5(31) – 6 or 149 Check Add the angle measures to verify that the angles are supplementary. mA + mB = 180 31 + 149 = 180 180 = 180  Answer:mA = 31, mB = 149 Example 2

  6. ALGEBRA Find the measures of two complementary angles if one angle measures six degrees less than five times the measure of the other. Example 2

  7. Concept

  8. Practice Problems • P. 50-51 2,15, 19, 21

  9. ALGEBRA Find x and y so thatKO and HM are perpendicular. Perpendicular Lines Example 3

  10. Perpendicular Lines 90 = (3x + 6) + 9x Substitution 90 = 12x + 6 Combine like terms. 84 = 12x Subtract 6 from each side. 7 = x Divide each side by 12. Example 3

  11. Perpendicular Lines To find y, use mMJO. mMJO = 3y + 6 Given 90 = 3y + 6 Substitution 84 = 3y Subtract 6 from each side. 28 = y Divide each side by 3. Answer: x = 7 and y = 28 Example 3

  12. Example 3

  13. p. 49 Read 2 paragraphs above this diagram Concept

  14. Interpret Figures A. Determine whether the following statement can be justified from the figure below. Explain. mVYT = 90 Example 4

  15. Interpret Figures B. Determine whether the following statement can be justified from the figure below. Explain. TYW andTYU are supplementary. Answer: Yes, they form a linear pair of angles. Example 4

  16. Interpret Figures C. Determine whether the following statement can be justified from the figure below. Explain. VYW andTYS are adjacent angles. Answer: No, they do not share a common side. Example 4

  17. A. Determine whether the statement mXAY = 90 can be assumed from the figure. A. yes B. no Example 4a

  18. B. Determine whether the statement TAU iscomplementarytoUAY can be assumed from the figure. A. yes B. no Example 4b

  19. Class Assignment • p. 50 – 52 4 -6, 17, 25, 29, 31 • HW p. 51-52 8-16 even, 20, 22, 26, Read 1-6 Take Notes

  20. Constructing Perpendiculars p. 55

More Related