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Circuit Lab.

Circuit Lab. Experiment-5 Phasor Analysis, Gain and Phase Response of a RC Circuit. Quiz. A(t)=5.sin(100 p t) B(t)=sin(100 p t- p ) Draw the graphic of signals. Write the phasor forms. x(t)= A . cos( w t + q ). Amplitude. Phase Shift. Angular Frequency. time (variable).

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Circuit Lab.

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  1. Circuit Lab. Experiment-5 Phasor Analysis, Gain and Phase Response of a RC Circuit

  2. Quiz • A(t)=5.sin(100pt) • B(t)=sin(100pt-p) • Draw the graphic of signals. • Write the phasor forms.

  3. x(t)=A.cos(wt+q) Amplitude Phase Shift Angular Frequency time (variable)

  4. Phasor Diagram Phasor Form: A=A1Ðf

  5. Example 1 • Es(t)=10.sin(wt) • V(t)=5.sin(wt+30o) • V=5Ð30o • I(t) = 2.sin(wt+120o) • I=2Ð120o 5 2 120o 30o

  6. 3 Example 2 • Es(t)=10.sin(wt) • A(t)=3.cos(wt) • A=? A(t)=3.sin(wt+90o) A=3Ð90o

  7. Euler’s Formula ejx=cos(x) + jsin(x)

  8. Ic(t) Example 3 E(t)=10.sin(wt) Vc(t)=? Ic(t)=? Vc(t)=E(t)=10.sin(wt) VC=10Ð0o Ic(t)=C.dVc(t)/dt = 10.C.w.cos(wt)=10.w.C.sin(wt+90o) IC=10.w.CÐ90o

  9. VC=10Ð0o IC=10.w.CÐ90o IC 10wC 10 VC

  10. Circuit Gain and Phase Response

  11. Gain: R=1 kW C=100 nF

  12. Phase: R=1 kW C=100 nF

  13. Example: R=1 kW, C=100 nF, |Vi|=10 V (p) f=1 kHz Gain ?, Phase? Gain: |Vo|=|Vi|.|H(jw)|=10.(0.8467)=8.467 V (p)

  14. Phase: Time Difference ? 360o  1ms 32.14o  x X = 89.28 ms

  15. Phasor Diagram Vi 10 32.14o 8.46 Vo

  16. Time Domain

  17. Measurement Setup GDS-1102 SFG-2120 f Hz 50 W OUT Vo Vi 1 kW 100 nF 10 V (p) or 5 V (p-p)

  18. MeasureCalculate

  19. Plot • f vs. Gain • f vs. Phase

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