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SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or)

SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or). SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or). If events are independent then…. A and B are Independent.

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SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or)

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  1. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or)

  2. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) If events are independent then… A and B are Independent

  3. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) If events are independent then… K and D are NOT Independent

  4. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) 6 8 14 8 28 36 34 50 16 P(Cat) = P(Dog) = P() = No because P(Cat and Dog)P(Cat)*P(Dog)

  5. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) 6 8 14 8 28 36 34 50 16 P(Cat) = P(Dog) = P() = P() = No because P(Cat|Dog)P(Cat) ; P(Dog|Cat)P(Dog)

  6. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) P() = P() =

  7. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) 5.) If P(A|B) = .35 and P(A and B) = .0525. a) Find P(B). b) If A and B are independent, find the P(A). If Independent…

  8. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) • 6. The P(A) = .15, P(B) = .25 and the P(A or B) = .3625. • Find the P(A and B) • b.) Are events A and B independent? Why? Why not? A and B are Independent

  9. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) 7.)

  10. SWBAT: Review of Probability (Test for Independence, Conditional Probability, And/Or) 8.) • A poll finds that 72% of Jacksonville consider themselves football fans. If you randomly pick two people from the population. • What is the probability the first person is a football fan and the second is as well? • That the first one is and the second one isn’t? = P(F) · P(F) = (.72)(.72) = P(F) · P(not F) = (.72)· (.28) = 0.2016

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