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Motion Along Two or Three Dimensions. Review. Equations for Motion Along One Dimension. Review. Motion Equations for Constant Acceleration. 1. 2. 3. 4. Slow Down. Giancoli Problem 3-9.
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Review • Equations for Motion Along One Dimension
Review • Motion Equations for Constant Acceleration • 1. • 2. • 3. • 4.
Giancoli Problem 3-9 • An airplane is traveling 735 km/hr in a direction 41.5o west of north. How far North and how far West has the plane traveled after 3 hours?
Problem Solving Strategy • Define your origin • Define your axis • Write down the given (as well as what you’re looking for) • Reduce the two dimensional problem into two one dimensional problems. • Choose which of the four equations would work best
Giancoli Problem 3-9 41.5
Giancoli Problem 3-9 41.5
Giancoli Problem 3-9 • In the Western direction • In the Northern direction 41.5
Giancoli Problem 3-9 41.5
X and Y components are independent • What happens along x does not affect y • What happens along y does not affect x • We can break down 2 dimensional motion as if we’re dealing with two separate one dimensional motions,
Serway Problem 3-25 • While exploring a cave, a spelunker starts at the entrance and moves the following distances. She goes 75.0m N, 250m E, 125m at an angle 30.0 N of E, and 150m S. Find the resultant displacement from the cave entrance. • NOT DRAWN TO SCALE
Serway Problem 3-25 • If you have the time and patience you can draw this system and solve the problem graphically. Or • Separate the vectors into their components. • NOT DRAWN TO SCALE
Serway Problem 3-25 • NOT DRAWN TO SCALE
Serway Problem 3-25 • Where • Substitute • NOT DRAWN TO SCALE
Serway Problem 3-25 • CAUTION • NOT DRAWN TO SCALE
Serway Problem 3-25 • NOT DRAWN TO SCALE
NOT DONE YET 2 degrees S of E • NOT DRAWN TO SCALE
Lets add another dimension • Serway 3-44 • A radar station locates a sinking ship at range 17.3 km bearing 136o clockwise from north. From the same station, a rescue plane is at horizontal range 19.6 km, 153o clockwise from north, with elevation 2.20 km. a) find position vector for the ship relative to the plane, letting i represent East, j represent north and k up. b) How far apart are the plane and the ship?
Serway 3-44 Vectors • S = Radar to ship • P=Radar to plane • Vector of Plane to ship? • Let D be plane to ship • Then
Velocity on a Curve • Velocity is tangent to the path
Velocity on a Curve • We can find direction of • velocity at any point in time • Velocity is changing
Acceleration on a Curve • Average Acceleration is changing • Acceleration is not constant
Special Cases • We’re not yet equipped to deal with non-constant acceleration. • So lets first examine some situations where acceleration is constant.
Projectile Motion • A projectile is any body that is given an initial velocity and then follows a path determined entirely by gravity and air resistance. • For simplicity lets ignore air resistance first. • The trajectory is the path a projectile takes. • We don’t care about how the projectile was launched or how it lands. We only care about the motion when it’s in free fall.
Projectile Motion - Trajectory • Follows Parabolic path (proof algebra) • Velocity is always tangent to the path • Since acceleration is purely downwards, motion is constrained to two dimension.
Projectile Motion - Components • Reduce the velocity vector to its components. • These components are orthogonal to each other so they have no effect on each other. • Motion along each axis is independent. • We can then use the equations of motion in one direction.
Equations for Motion with constant Acceleration • x-axis • 1. • 2. • 3. • 4. • y-axis • 1. • 2. • 3. • 4.
But Wait • In projectile motion, only gravity is acting on the object • a=-g=-9.80m/s2 • What are the components of this acceleration
But Wait • In projectile motion, only gravity is acting on the object • a=-g=-9.80 m/s2 • What are the components of this acceleration • ay=-9.80 m/s2 • ax= 0 there is NO x-component
Equations of Motion for Projectile Motion • x-axis (ax=0) • 1. • 2. • 3. • 4. • y-axis (ay=-g) • 1. • 2. • 3. • 4.
Equations of Motion for Projectile Motion • x-axis (ax=0) • 1. • 2. • y-axis (ay=-g) • 1. • 2. • 3. • 4.
Example • A motorcycle stuntman rides over a cliff. Just at the cliff edge his velocity is completely horizontal with magnitude 9.0 m/s. Find the motorcycles position, distance from the cliff edge, and velocity after 0.50s.
List the given • Origin is cliff edge • a=-g=-9.80m/s2 • At time t=0s • At time t=0.50s