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LAB QUIZ  V = I R

LAB QUIZ  V = I R. 1.) You measured the voltage difference and current across a resistor and got values of 1.5 V and 0.06 amps, respectively. What is the value in ohms of your resistor? 25 ohms

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LAB QUIZ  V = I R

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  1. LAB QUIZ V = I R 1.) You measured the voltage difference and current across a resistor and got values of 1.5 V and 0.06 amps, respectively. What is the value in ohms of your resistor? 25 ohms 2.) Label circuits on right as A) B) B )Series A) parallel. 3.) What happens to circuit A (other bulbs get brighter) and circuit B (all go out) when one of their 3 lightbulbs is removed? 4.) Color first signif. digit second signif. digit multiplier yellow 3 3 103 red 2 2 102 brown 1 1 101 black 0 0 100 What is the resistance of this resistor? 33 ohms

  2. Combination Circuits Rtotal or Requivalent • Combine parallel resistors • 2) Combine series resistors 3 Ω 11 Ω

  3. Combination Circuits Answer : 18 Ω

  4. Combination Circuits 18 Ω 4 Ω

  5. Combination Circuits Analyze the following circuit and determine the values of the total resistance, total current, and the current at and voltage drops across each individual resistor.

  6. Power: Putting Charges to Work watt (W) = joule second 60 watt light bulb - 60 joules of energy delivered to the light bulb every second 120 watt light bulb - draws 120 joules of energy every second

  7. Calculating Power

  8. Calculating Power • Determine the ... • ... current in a 60-watt bulb plugged into a 120-volt outlet. • b. ... current in a 120-watt bulb plugged into a 120-volt outlet. • c. ... power of a saw that draws 12 amps of current when plugged into a 120-volt outlet. • d. ... power of a hair dryer that draws 6 amps of current when plugged into a 120-volt outlet. • e. ... current in a 1000-watt television when plugged into a 120-volt outlet. 0.5 amps 1 amps 1440 W 720 W 8.3 amps

  9. Calculating Power

  10. ENERGY: kilowatt•hour The kilowatt•hour kilowatt is unit of power hour is unit of time kilowatt • hour is unit of Power • time (ENERGY) A utility company in the United States is responsible for assuring that the electric potential difference across the two main wires of the house is 110 to 120 volts. Maintaining this difference in potential requires energy. It is a common misconception that the utility company provides electricity in the form of charge carriers or electrons.

  11. ENERGY: kilowatt•hour Alfredo deDarke sleeps with a 7.5-Watt night light bulb on. He turns it on before getting in bed and turns it off 8 hours later. Determine the amount of energy used during one evening in units of kiloWatt•hours. 7.5 W x 1 kW x 8 hours = 0.06 kW•hr 1000 W How much energy do you use playing with a Wii video game player (220 W) for 6 hours? 0.220 kW x 6 hr = 1.32 kW•hr

  12. Power (watt) / Energy (kilowatthour)/ Cost Your 60-watt light bulb is plugged into a 110-volt household outlet and left on for 3 hours. The utility company charges you $0.11 per kiloWatt•hr. Explain how you can calculate the cost of such a mistake. Answer on next slide

  13. Power (watt) / Energy (kilowatthour)/ Cost Answer The energy consumed can be determined from knowledge of the power (60 Watts) and the time (3 hrs). The energy consumed is 180 Watt•hr or 0.180 kW•hr. Each kW•hr costs 11 ¢ pr $0.11. Now simply multiply the cost per ¢ by the amount of¢ of energy consumed. The result is just a little short of 2 cents.

  14. Power (watt) / Energy (kilowatthour)/ Cost Alfredo deDarke often leaves household appliances on for no good reason (at least according to his parents). The deDarke family pays 10¢/kilowatt-hour (i.e., $.10/kW•hr) for their electrical energy. Express your understanding of the relationship between power, electrical energy, time, and costs by filling in the table below.

  15. The power rating of a resistor can be determined from any one of the following formulae: 2 4 1.2 6

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