Introduction

1. Introduction Finding the solutions to a system of linear equations requires graphing multiple linear inequalities on the same coordinate plane. Most real-world applications dealing with linear inequalities are actually systems of linear inequalities where at least one of the conditions is that one of the variables must be greater than 0. 2.3.2: Solving Systems of Linear Inequalities

2. Key Concepts A system of inequalities is two or more inequalities in the same variables that work together. The solution to a system of linear inequalities is the intersection of the half planes of the inequalities. The solution will be the set of all points that make all the inequalities in the system true. Graph each inequality and include the correct shading. 2.3.2: Solving Systems of Linear Inequalities

3. Key Concepts, continued Look for the area where the shading of the inequalities overlaps; this is the “solution”. Remember to add constraints to the system that aren’t explicitly stated in the problem context but that make sense for the problem. 2.3.2: Solving Systems of Linear Inequalities

4. Common Errors/Misconceptions incorrectly graphing one or more of the inequalities in the system not seeing the solution or where the intersections occur forgetting to include constraints or boundaries that make sense for the context of the problem 2.3.2: Solving Systems of Linear Inequalities

5. “Wise Notes” ≥ ≤ Solid Line > < Dashed Line <- - - - - - - -> If x is present, vertical line Ex: x < 3 If y is present, horizontal line Ex: y >3 Use (0,0) as test points If true, shade with sign. If false, shade opposite sign 2.3.2: Solving Systems of Linear Inequalities

6. Guided Practice Example 1 Solve the following system of inequalities graphically: 2.3.2: Solving Systems of Linear Inequalities

7. Guided Practice: Example 1, continued Graph the line x + y = 10. Use a dashed line because the inequality is non-inclusive (greater than). 2.3.2: Solving Systems of Linear Inequalities

8. Guided Practice: Example 1, continued Shade the solution set. First pick a test point. Choose a point that is on either side of the line. Test point: (0, 0) 2.3.2: Solving Systems of Linear Inequalities

9. Guided Practice: Example 1, continued Then, substitute that point into the equality x + y > 10. If the test point makes the inequality true, shade the region that contains that point. If the test point makes the inequality false, shade on the opposite side of the line. 2.3.2: Solving Systems of Linear Inequalities

10. Guided Practice: Example 1, continued Since the point (0, 0) makes the inequality false, shade the opposite side of the line. The shaded region represents the solutions for x + y > 10. 2.3.2: Solving Systems of Linear Inequalities

11. Guided Practice: Example 1, continued Graph the line 2x – 4y = 5 on the same coordinate plane. Use a dashed line because the inequality is non-inclusive (greater than). 2.3.2: Solving Systems of Linear Inequalities

12. Guided Practice: Example 1, continued Shade the solution set. First pick a test point. Choose a point that is on either side of the line. Test point: (0, 0) 2.3.2: Solving Systems of Linear Inequalities

13. Guided Practice: Example 1, continued Then, substitute that point into the inequality 2x – 4y = 5. If the test point makes the inequality true, shade the region that contains that point. If the test point makes the inequality false, shade on the opposite side of the line. 2.3.2: Solving Systems of Linear Inequalities

14. Guided Practice: Example 1, continued Since the point (0, 0) makes the inequality false, shade the opposite side of the line. The second shaded region represents the solutions for 2x – 4y = 5. 2.3.2: Solving Systems of Linear Inequalities

15. Guided Practice: Example 1, continued Find the solutions to the system. The overlap of the two shaded regions, which is darker, represents the solutions to the system: A possible solution to this system is (14, 2) because it satisfies both inequalities. 2.3.2: Solving Systems of Linear Inequalities

16. Guided Practice: Example 1, continued ✔ 2.3.2: Solving Systems of Linear Inequalities

17. Guided Practice: Example 4 Create the system of inequalities given the example below. Let x = the number of oil paintings he makes. Let y = the number of watercolor paintings he makes. It might be helpful to create a table: 2.3.2: Solving Systems of Linear Inequalities

18. Guided Practice: Example 4, continued Now, think about what must always be true of creating the paintings: there will never be negative paintings. Add these two constraints to the system: x ≥ 0 and y ≥ 0. 2.3.2: Solving Systems of Linear Inequalities

19. Guided Practice: Example 4, continued Graph the system on the same coordinate plane. Start by graphing the first two inequalities. 2.3.2: Solving Systems of Linear Inequalities

20. Guided Practice: Example 4, continued Now apply the last two constraints: x ≥ 0 and y ≥ 0. This means the solution lies in the first quadrant. 2.3.2: Solving Systems of Linear Inequalities

21. Guided Practice: Example 4, continued The solution is the darker shaded region; any points that lie within it are solutions to the system. The point (1, 1) is a solution because it satisfies both inequalities. The artist can create 1 oil painting and 1 watercolor painting given the time constraints he has. Or, he can create no oil paintings and 4 watercolor paintings, (0, 4). However, he cannot create 4 oil paintings and 1 watercolor painting, because the point (4, 1) only satisfies one inequality and does not lie in the darker shaded region. ✔ 2.3.2: Solving Systems of Linear Inequalities