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√ (30)(0.7)(320). (5)(-3)(y)(xy 4 ). S = sprinklr space: 6 L = sprinklr row: 8 P – precipitation rate: 30 F = water flow (?). (2712.50)(1.085) 2. (30)(6)(8). (93.6). $9 $.
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√(30)(0.7)(320) (5)(-3)(y)(xy4) S = sprinklr space: 6 L = sprinklr row: 8 P – precipitation rate: 30 F = water flow (?) (2712.50)(1.085)2 (30)(6)(8) (93.6)
$9 $ 1200(1.063)46 –1200 = 5lb 18lb .063 = 297,450.30 50 ? = (1 – 0.15), means: decrease at 15% 4wk 14wk 3 2 m = 16 4 = 144 x
2 5 m = – 1 2 2 5 y + 7 = – (x – 5) m = 2 5 y = – x – 5 Parallel: same slope 2 5 + y = –5 y = typing speed x = # of weeks typing + 21 = typing speed w/ no experience 1 5 m = Perpendicular: opp, reciprocal slope
STAT – EDIT L1 L2 STAT – Calc - #4 ENTER y = value of art x = yearly increase + 3,492 = initial price of the art piece a = -1.0346 decrease 1° y = total cost per visit x = length of visit (hrs) + 40.5 = flat rate price STAT – EDIT L1 L2 STAT – Calc - #4 ENTER a= .0335860516 b= 45.78682467 (18000)( .0335860516) + 45.78682467 = 650.3357535
(y)bds: 9 18 (x)ft: 6 12 Graph it: y = -5x – 1 y = -1/5x – 3 3 2 m = STAT – EDIT L1 L2 STAT – Calc - #4 ENTER a= 1.821428571 b= 28.75 STAT – EDIT L1 L2 STAT – Calc - #4 ENTER a= .5442857143 b= 30.38095238
Work backwards Graph it:
Graph it, for example: y = 2x – 5 y = 2x + 5 48 = 8x + 16 x = 4 y = 11(4) + 16
y = 10x + 60 y = 16x 16x = 10x + 60 x = 10 Matrix: [A]-1[B] 3c + 2a = 120 5c + 1a = 95 {[2] [1]} Matrix: [A]-1[B] {[10] [45]} Matrix: [A]-1[B] {[3.2] [-4]}
= 110,0408.08 Go to the table: x = 7 y = 7.9959 thousands