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Magnetism. Charged particles passing through magnetic fields experience a force due to that magnetic field. The direction of the force is perpendicular to both the direction of travel and the direction of the magnetic field. The magnitude of the force is given by: F = B · v · q · sin θ
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Magnetism • Charged particles passing through magnetic fields experience a force due to that magnetic field. • The direction of the force is perpendicular to both the direction of travel and the direction of the magnetic field. • The magnitude of the force is given by: • F = B·v·q·sinθ • F is the force on the charged particle (Newtons) • B is the strength of the magnetic field (Tesla) • v is the velocity of the charged particle (m/s) • q is the charge of the particle (C) • Θ is the angle between the direction of the magnetic field and the velocity vector (degrees)
Magnetism Sample Problem Problem • A particle with a charge of +8.4 μC and a speed of 45 m/s enters a uniform magnetic field whose magnitude is 0.30 T. • For each of the cases in the drawing, find the magnitude and direction of the magnetic force on the particle. Solution • The equation relating Force, Magnetic Field Strength, Velocity, and Charge is: • F = B·v·q·sinθ • Substituting known variables: • Part a) F= (0.30 T)(45 m/s)(8.4 x 10-6 C)(sin30o) = 5.67 x 10-5 N, out of page • Part b) F = (0.30 T)(45 m/s)(8.4 x 10-6 C)(sin90o) = 11.3 x 10-5 N, out of page • Part c) F = (0.30 T)(45 m/s)(8.4 x 10-6 C)(sin150o) = 5.67 x 10-5 N, out of page