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Coming Up:. Today : Review Quiz 2 (if not done on Gateway Quiz #2 day) Lecture on Section 2.5 : Word problems! NOTE: This homework is due at the beginning of the next class session. Coming up the week after next : Test 1 on all sections covered this semester
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Coming Up: Today: • Review Quiz 2 (if not done on Gateway Quiz #2 day) • Lecture on Section 2.5: Word problems! • NOTE: This homework is due at the beginning of the next class session. Coming up the week after next: • Test 1 on all sections covered this semester • Section 2.6 will be covered at the next class session. • At the class after that, we will review for Test 1 and start the practice test. (Test 1 covers everything through 2.6) Reminder: April 3 is the last day to drop any of your semester classes without a grade of “F” on your transcript.
Online Quiz 2 Results: • Average class score after partial credit: __________ • Commonly missed questions: #_________________ Grade Scale • If you got less than 70% on Quiz 2, make sure to go over your quiz with me or a TA sometime today or tomorrow to help you prepare for the upcoming midterm test.
Gateway Quiz Retake Facts • MUST pass with 100% to pass Math 010 • Two attempts to pass in class • If not passed during those two attempts: • One attempt per week • Eight weeks = eight chances to pass • Outside of class time Math TLC Open Lab open M-Th 8:00 am to 6:30 pm Jarvis Hall Science Wing 203
Didn’t pass your Gateway Quiz? Hereare the next steps: • Go over the incorrect answers on your previous attempts with a TA (and get their signature) in the Math TLC Open Lab (JHSW 203) • Take another Practice Gateway Quiz • Go over any incorrect answers on the practice attempts with a TA in the Math TLC Open Lab • Have a TA in the Math TLC Open Lab sign you up for a retake time
Gateway Quiz Retake Times(Beginning Monday, March 26) • Mondays • 2:30 pm • 3:35 pm • Tuesdays • 1:25 pm • 3:35 pm • Wednesdays • 10:10 am • 1:25 pm • Thursdays • 10:10 am • 2:30 pm SIGN UP IN THE MATH TLC OPEN LAB! If NONE of the above times work for you… email Krystle Mayer, Math TLC Manager, (mayerkr@uwstout.edu) to set up a date and time
CLOSE YOUR LAPTOPS
Section 2.5: Application Problems: General strategy for problem solving: • Understand the problem • Read and reread the problem • Choose a variable to represent the unknown • Construct a drawing, whenever possible • Translate the problem into an equation • Solve the equation • Interpret the result • Check solution • State your conclusion
Example 1: Understand The product of twice a number and three is the same as the difference of five times the number and ¾. Find the number. - Read and reread the problem. - Choose a variable to represent your unknown. If we let x = the unknown number, then “twice a number” translates to 2x, “the product of twice a number and three” translates to 2x· 3, “five times the number” translates to 5x, and “the difference of five times the number and ¾” translates to 5x - ¾ .
Example (cont.) Translate The product of the difference of is the same as twice a number 5 times the number and 3 and ¾ 2x · 3 = 5x – ¾
Example (cont.) Solve 6x + (-5x) = 5x + (-5x) – ¾(add –5x to both sides) 2x· 3 = 5x – ¾ 6x = 5x – ¾(simplify left side) x = - ¾(simplify both sides) Now CHECK your answer (see if both sides produce the same answer when you put -3/4 in place of x): Left side: 2x·3= (2·-3/4)·3 = -6/4 · 3 = -3/2 · 3= -9/2 Right side:5x – 3/4 = 5·3/4 – 3/4 = -15/4 – 3/4= -18/4 = -9/2
Consider the difference between the last problem: The product of twice a number and three is the same as the difference of five times the number and ¾. Find the number. Equation: 2x· 3 = 5x – ¾ (Answer = -3/4) And this problem: Twice the product of a number and three is the same as five times the differenceofthe number and ¾. Find the number. Equation: 2(x· 3) = 5(x – ¾) (Answer = -15/4)
Sample homework problem: How would you set this problem up? 5(x – 4) = 4 + 5x + 4x
Example Understand A car rental agency advertised renting a Toyota Prius for $25 per day and $0.20 per mile. If you rent this car for 2 days, how many miles can you drive on a $100 budget? Read and reread the problem. Just to get an idea of what’s going on in this problems, let’s start by considering what the cost would be if we were to drive a total of 100 miles over the 2 days. In this case our equation for the total cost would come from taking twice the daily rate and adding the fee for mileage to get 2(25)+ 0.20(100) = 50.00 + 20 = $70.00. This gives us an idea of how the cost is calculated, and we also now know that if we have $100 to spend, we can drive more than 100 miles.
Example (cont.) Translate Daily costs maximum budget is equal to mileage costs plus 2(25) + 0.20x = 100 So to generalize this specific example of 100 miles, if we let x = the number of miles driven, then 0.29x = the cost for mileage driven. To do this problem without a calculator, we will want to convert the decimal 0.20 into the fraction 20/100.
Example (cont.) Solve (subtract 50 from both sides) 50 – 50 + 20/100 x = 100 – 50 (multiply both sides by 100/20) 2(25) + 20/100x= 100 50 + 20/100x = 100(simplify left side) 20/100 x = 50(simplify both sides) x= 50∙5 = 250(simplify both sides)
Example (cont.) Interpret Check: If we replace “number of miles” in the problem with 250, then 50 + 0.20(250) = 50 + 50, which is equal to our budget of $100. State your answer: The maximum number of miles we can drive is 250.
Hint: Start by drawing a picture. Answer: First piece is 4 inches, second is 12, third is 20.
Example: The sum of three consecutive integers is 366. What are the three integers? • Solution: • Call the first integer x. • Then what is the next consecutive integer? • x + 1 • And the third one? • x+ 2 • So the sum would be what? • x + x + 1 +x+ 2 • This simplifies to 3x + 3 • And the equation would be what? • 3x + 3 = 366
Example (cont): The sum of three consecutive integers is 366. What are the three integers? • Solution (cont): • Now solve the equation • 3x + 3 = 366 • 3x = 363 • x = 363/3 = 121 • Now answer the question: • First integer = x • x = 121 • Second integer = x + 1 • = 122 • Third integer = x + 2 • = 123
Example (cont): The sum of three consecutive integers is 366. What are the three integers? • Now check your solution: (121, 122, 123) • Are these three numbers integers? • Yes • Are they consecutive? • Yes • Do they add up to 366? • 121 + 122 + 123 = 243 + 123 = 366 • Yes
Example: Now let’s change the problem slightly: The sum of three consecutive even integers is 366. What are the three integers? • Solution: • Call the first integer x. • Then what is the next consecutive even integer? • x + 2 • And the third one? • x+ 4 • So the sum would be what? • x + x + 2 +x+ 4 • This simplifies to 3x + 6 • And the equation would be what? • 3x + 6 = 366
Example (cont): The sum of three consecutive even integers is 366. What are the three integers? • Solution (cont): • Now solve the equation • 3x + 6 = 366 • 3x = 360 • x = 360/3 = 120 • Now answer the question: • First integer = x • x = 120 • Second integer = x + 2 • = 122 • Third integer = x + 4 • = 124
Example (cont): The sum of three consecutive integers is 366. What are the three integers? • Now check your solution: (120, 122, 124) • Are these three numbers integers? • Yes • Are they even? • Yes • Do they add up to 366? • 120 + 122 + 124 = 242 + 124 = 366 • Yes
Reminder: This homework on Section 2.5 is due at start of next class session. You may want to come in to the lab for help on this homework. Many students find that these problems take a bit longer to figure out than previous assignments. Also, please remember to come in to the lab for your Gateway quiz review and get your worksheet signed, then sign up with Krystle Mayer to take it sometime this week.
Note to instructors: The remaining slides contain additional problems from today’s homework that you might want to cover if time allows.