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Bertrand's Paradox Ian T. Flockhart

Bertrand's Paradox Ian T. Flockhart. -1. 1. D. A. -1. 1. 1/2. π/3. -1. 1. D. A. -1. 1. 0 < D < ½ π/3 < A < π/2. P(E) = P(D < ½) = ½. D. A. -1. 1. 0 < D < ½ π/3 < A < π/2. P(E) = P(D < ½) = ½. P(E) = P(A > π/3 ) = 1/3. D. A. -1. 1. 0 < D < ½ π/3 < A < π/2.

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Bertrand's Paradox Ian T. Flockhart

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  1. Bertrand's ParadoxIan T. Flockhart

  2. -1 1

  3. D A -1 1

  4. 1/2 π/3 -1 1

  5. D A -1 1 0 < D < ½ π/3 < A < π/2

  6. P(E) = P(D < ½) = ½ D A -1 1 0 < D < ½ π/3 < A < π/2

  7. P(E) = P(D < ½) = ½ P(E) = P(A > π/3) = 1/3 D A -1 1 0 < D < ½ π/3 < A < π/2

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