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11/7/12 Unit 2 Triangles

11/7/12 Unit 2 Triangles. Converse of P ythagorean Theorem. Given the lengths of three sides, how do you know if you have a right triangle?. Given A = 6, B=8, and C=10, describe the triangle. If A 2 + B 2 = C 2 6 2 +8 2 = 10 2 36 + 64 = 100

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11/7/12 Unit 2 Triangles

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  1. 11/7/12 Unit 2 Triangles Converse of Pythagorean Theorem

  2. Given the lengths of three sides, how do you know if you have a right triangle? Given A = 6, B=8, and C=10, describe the triangle. If A2 + B2 = C2 62 +82 = 102 36 + 64 = 100 This is true, so you have a right triangle. C A B

  3. Given A = 4, B = 5, and C =6, describe the triangle. C2 < A2 + B2 62 < 42 + 52 36 < 16 + 25 36 < 41, so we have an acute triangle. If C2 < A2 + B2, you have an acute triangle. A B C

  4. Given A = 4, B = 6, and C =8, describe the triangle. C2> A2 + B2 82> 42 + 62 64 > 16 + 36 64 >52, so we have an obtuse triangle. If C2> A2 + B2, you have an obtuse triangle. A B C

  5. 1) A=9, B=40, C=41 2) A=10, B=15, C=20 3) A=2, B=5, C=6 4) A=12, B=16, C=20 5) A=11, B=12, C=14 6) A=2, B=3, C=4 7) A=1, B=7, C=7 8) A=90, B=120, C=150 Describe the following triangles as acute, right, or obtuse right obtuse obtuse right C acute A obtuse acute right B

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