1 / 6

Conservation of Momentum

Conservation of Momentum. Chapter 6 section 2. Momentum is Conserved. With in a closed system, momentum is conserved. The momentum gained by an object must come from an another object losing momentum. Billiards can be used to describe the concept. Law of Conservation of Momentum.

malise
Download Presentation

Conservation of Momentum

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Conservation of Momentum Chapter 6 section 2

  2. Momentum is Conserved • With in a closed system, momentum is conserved. • The momentum gained by an object must come from an another object losing momentum. • Billiards can be used to describe the concept.

  3. Law of Conservation of Momentum • Law of Conservation of Momentum – The total momentum of all objects interacting with one another remains constant regardless of the nature of the forces between the objects. • In other words, the total momentum before a collision is equal to the total momentum after a collision.

  4. Conservation of Momentum Equation Total initial momentum = Total final Momentum

  5. Example Problem • A 76 kg boater, initially at rest in a stationary 45 kg boat, steps out of the boat and onto the dock. If the boater moves out of the boat with a velocity of 2.5m/s to the right, what is the final velocity of the boat?

  6. Example Problem Answer m1v1i + m2v2i = m1v1f + m2v2f Since boat and boater are initial at rest the total momentum before is equal to zero. 0 = m1v1f + m2v2f 0 = (76kg)(2.5m/s)+(45kg)(v2f) V2f = -4.2m/s V2f = 4.2m/s to the left

More Related