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Modeling of Electrical Circuits. C. L. +. V 1. -. R 1. R 2. Q q. Q q2. Current in the resistor R 1 =. q ve q 2 : Gen. charges. Example 3.1:. V 1 : Input. L=3.4 mH, C=286 µ F, R 1 =3.2 Ω , R 2 =4.5 Ω. D(s)=0.02618s 3 +26.288s 2 +11188.81s=0.

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  1. Modeling of Electrical Circuits C L + V1 - R1 R2 Qq Qq2 Current in the resistor R1 = q ve q2 : Gen. charges Example 3.1: V1: Input L=3.4 mH, C=286 µF, R1=3.2 Ω, R2=4.5 Ω D(s)=0.02618s3+26.288s2+11188.81s=0 Eigenvalues: 0, -502.06±418.70i (ξ=0.768)

  2. In op-amp input, resistance is too high C1 R3 C2 R1 V1 V2 R2 - + Example3.2 Input :V1 Generalized charges: q1, q2, q3 Also, in op-amp: V+=V-=0

  3. R1=15.9 kΩ, R2=837 Ω, R3=318 kΩ, C1=C2=0.005 µF Eigenvalues: 0, -628.93±12561.76i (ξ=0.05)

  4. C R2 R R1 V2 V2 V1 V1 V1 R - - - C + + + V2

  5. R R R R R R R R R V3 V2 V1 Vc - - V1 - + + + Vc + V1 - Vc V2 V2

  6. C3 R2 R3 R1 R R R R4 - - - V1 R + + + C4 V2 - + PID control circuit

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