How tall is it?

1. Taylor Schmelzle A.J. Leatherwood Valerie Barreau Adam Cooper 6th Period 9 March 2009 How tall is it?

2. 3o degrees • Taylor • Calculations: • Long Leg = √ 3 × short leg 28 = √3 × t 28 / √3 = t ≈ 16.17 ft + 5 ft ≈ 21.17 ft • Tangent t = opposite / adjacent tan 30= t / 28 28 (tan 30) = t t ≈ 21.17 ft 30 Degrees 28ft.

3. 60 degrees • A. J. • Calculations: long leg= √3 × 16 ft long leg=16 √3 long leg≈27.71 ft 27.71ft +63 inches 27.71 ft +5.25 ≈ 32.96 ft • Tangent x = opposite/adjacent Tan 60= x ft/16 ft 16 (Tan 60) = x x ≈ 27.71 ft 27.71 ft + 5.25 ft ≈ 32.96 ft 60 degrees 16 ft

4. 45 degrees Valerie Special Right Triangles Calculation: hypotenuse = √2 × leg hypotenuse= 24√2 ≈ 33.94 feet 33.94 feet + 5 feet ≈ 38.94 ft Tangent x= opposite / adjacent tan 45 = x / 24 24( tan 45) = x x ≈ 38.94 ft 45 degrees 24 ft

5. 50 degrees • Adam • Calculations: • Long leg = √3 × short leg 18 = √3 × a 18 / √3 = a ≈ 10.39 + 5.25 ≈ 15.64 ft • Tangent x = opposite / adjacent tan 50 = a / 18 18 (tan 50) = a a ≈ 15.64 ft 50 degrees 18 ft

6. Conclusion Slide We each measured a different angle of the building and counted the distance between us and the structure. We then used formulas for special right triangles and trigonometry to determine approximately how tall the building is. By adding the four averages : 32.96 ft + 38.94 ft + 21.17 ft + 15.64=108.71 then divide by four: 108.71 / 4 = 27.18 ft In conclusion, the building is approximately 27.18 ft tall.