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Geometry

Geometry. 11.5 Circumference and Area of Circles. Let’s talk about Pi………. Pi is the ratio of the circumference of a circle to its diameter. This ratio is the same for all circles. The symbol for pi is π. circumference. C. π =. d. •. d. The Value of Pi………. PI

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Geometry

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  1. Geometry 11.5 Circumference and Area of Circles

  2. Let’s talk about Pi……… Pi is the ratio of the circumference of a circle to its diameter. This ratio is the same for all circles. The symbol for pi is π circumference C π = d • d

  3. The Value of Pi……… PI 3. 141592653589793238462643383279502884197169399375105820974944 592307816406286208998628034825342117067982148086513282306647 093844609550582231725359408128481117450284102701938521105559 644622948954930381964428810975665933446128475648233786783165 271201909145648566923460348610454326648213393607260249141273 724587006606315588174881520920962829254091715364367892590360 011330530548820466521384146951941511609433057270365759591953 092186117381932611793105118548074462379962749567351885752724 891227938183011949129833673362440656643086021394946395224737 190702179860943702770539217176293176752384674818467669405132 000568127145263560827785771342757789609173637178721468440901 224953430146549585371050792279689258923542019956112129021960 864034418159813629774771309960518707211349999998372978049951 Pi is an IRRATIONAL NUMBER …and so on, never terminating, never repeating…….

  4. Approximate Value of Pi……… Usually in this class, we will leave pi as a constant. For example, we may say that the area of a circle is 5π, or 6aπ, or 12.6π, etc. The π symbol will remain in our expression. When you need to use a decimal approximation of pi: π ≈ 3.14 When you need to use a fractional approximation of pi: 22 π ≈ 7

  5. Circle Formulas Area = πr² Circumference = 2πr = d π r d •

  6. 5 Exercises C = 12π r = 8 A = 16π 6 4 8 1. A = π(5)² = 25π 2. r = ½(12) = 6 3. r = √16 = 4 4. A = π(8)² = 64π C = dπ = 10π A = π(6)² = 36π C = 2(4)π = 8π C = dπ = 16π

  7. Exercises C = 100π A = 121π 50 11 5. r = ½(100) = 50 6. r = √121 = 11 A = π(50)² = 2500π C = 2(11)π = 22π

  8. Exercises Find the diameter of a pipe if the area of a cross-section is 50.24 cm2 (Use 3.14 for pi Find the radius of a pizza pan if its circumference is 12.56 ft. (Use 3.14 for pi) 7. A = πr² 8. C = dπ 50.24 = 3.14r² 12.56 = 3.14d r² = 16 d = 4 r = 4 r = 2 d = 8

  9. Exercises Nick wants to enclose his brand new GEO in a circular fence that costs $2.95/ft. If the circle has a radius of 3.5 ft., how much will the fencing cost? (use 22/7 for π.) We need to find Circumference: C = 2(3.5)(22/7) C = 7(22/7) $64.90 C = 22 ft. Cost = 22 • 2.95 = $64.90

  10. Homework pg. 448 #1-16, 23a, 26 Use formulas

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