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This physics problem involves a competition between two teams of three members each. The goal is to determine the final velocity of a 120-kg cart when propelled by three 60-kg individuals jumping off with a velocity of 10 m/s.
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Jumping from a CartCompetitionsp 4, page 248 Created for CVCA Physics By Dick Heckathorn 12 Jan 2K + 5
The Challenge A competition is held between two teams of three 60-kg members each. The teams will take turns climbing onto the cart and jumping off. They want to see whose cart of mass 120-kg will be moved fastest when propelling it with a jump.
Team A will start at the left end of the cart that is free to roll without friction, run to the right and jump off with a velocity of 10 m/s with respect to the cart. One member of team B will start at the left end of the cart, run to the right and jump off with a velocity of 10 m/s followed by the second and then the third member.
A 120-kg cart is at rest. Three 60-kg people run to the right and together jump off the cart at 10 m/s. What is the final velocity of the cart?
Team A Three 60-kg people run to the right and together jump off the cart at 10 m/s. v = 10 m/s + V v = V Let ‘V’ be the final velocity of the cart with respect to the earth. Let ‘v’ be the final velocity of the three people with respect to the earth.
Team A v= v=10 m/s+ V V
Team B v1= v1= 10 m/s + V1 V1 Let ‘v1’ be the final velocity of the first student with respect to the earth. Let ‘V1’ be the final velocity of the cart with respect to the earth.
Team B v1= v1= 10 m/s + V1 V1
Team B v2= 10 m/s + V2 v2= V2 v1= 8 m/s Let ‘v2’ be the final velocity of the second student with respect to the earth. Let ‘V2’ be the final velocity of the cart with respect to the earth.
Team B v2= 10 m/s + V2 V2 v1= 8 m/s
Team B v3= 10 m/s + V3 v3= V3 Let ‘v3’ be the final velocity of the third student with respect to the earth. Let ‘V3’ be the final velocity of the cart with respect to the earth.
Team B v2=5.5 m/s v3= 10 m/s + V3 v1=8 m/s V3