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Do Now 12/12/18. Take out HW from last night. Text p. 245, #9-18 all, 20 & 27 Copy HW in your planner. Text p. 251, #4-22 evens, 31
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Do Now 12/12/18 • Take out HW from last night. • Text p. 245, #9-18 all, 20 & 27 • Copy HW in your planner. • Text p. 251, #4-22 evens, 31 • In your notebook, answer the following question. A farmer plants corn and wheat on a 180-acre farm. The farmer wants to plant three times as many acres of corn as wheat. Write a system of linear equations that represents this situation. How many acres of each crop should the former plant? x = y =
A farmer plants corn and wheat on a 180-acre farm. The farmer wants to plant three times as many acres of corn as wheat. Write a system of linear equations that represents this situation. How many acres of each crop should the farmer plant? x + y = 180 x = x = 3y y =
Learning Goal • Students will be able to write and graph systems of linear equations. Learning Target • Students will be able to solve systems of linear equations by elimination
Section 5.1“Solve Linear Systems by Graphing” Linear System– consists of two more linear equations. x + 2y = 7 Equation 1 3x – 2y = 5 Equation 2 A solution to a linear system is an ordered pair (a point) where the two linear equations (lines) intersect (cross).
“Solve Linear Systems by Substituting” Equation 1 x – 2y = -6 x = -6 + 2y Equation 2 4x + 6y = 4 4x + 6y = 4 4(-6 + 2y)+ 6y = 4 Substitute -24 + 8y + 6y = 4 -24 + 14y = 4 y = 2 x – 2y = -6 Equation 1 Substitute value for x into the original equation x = -6 + 2(2) x = -2 (-2) - 2(2) = -6 -6 = -6 4(-2) + 6(2) = 4 4 = 4 The solution is the point (-2,2). Substitute (-2,2) into both equations to check.
During a football game, a bag of popcorn sells for $2.50 and a pretzel sells for $2.00. The total amount of money collected during the game was $336. Twice as many bags of popcorn sold compared to pretzels. How many bags of popcorn and pretzels were sold during the game? y = 2x x = $2.50y + $2.00x = $336 y = 96 bags of popcorn and 48 pretzels
“How Do You Solve a Linear System???” (1) Solve Linear Systems by Graphing (5.1) (2) Solve Linear Systems by Substitution (5.2) (3) Solve Linear Systems by ELIMINATION!!! (5.3)
Section 5.3 “Solve Linear Systems by Elimination” • ELIMINATION- adding or subtracting equations to obtain a new equation in one variable.
“Solve Linear Systems by Elimination” ADDITION Eliminated 2x + 3y = 11 Equation 1 + -2x + 5y = 13 Equation 2 8y = 24 y = 3 2x + 3y = 11 Equation 1 Substitute value for y into either of the original equations 2x + 3(3) = 11 2x + 9 = 11 x = 1 2(1) + 3(3) = 11 11 = 11 -2(1) + 5(3) = 13 13 = 13 The solution is the point (1,3). Substitute (1,3) into both equations to check.
“Solve Linear Systems by Elimination” Eliminated SUBTRACTION 4x + 3y = 2 Equation 1 _ + -5x + -3y = 2 5x + 3y = -2 Equation 2 -x = 4 x = -4 4x + 3y = 2 Equation 1 Substitute value for x into either of the original equations 4(-4) + 3y = 2 -16 + 3y = 2 y = 6 4(-4) + 3(6) = 2 2 = 2 5(-4) + 3(6) = -2 -2 = -2 The solution is the point (-4,6). Substitute (-4,6) into both equations to check.
“Solve Linear Systems by Elimination” Eliminated 8x - 4y = -4 Equation 1 Arrange like terms + -3x + 4y = 14 4y = 3x + 14 Equation 2 5x = 10 x = 2 8x - 4y = -4 Equation 1 Substitute value for x into either of the original equations 8(2) - 4y = -4 16 - 4y = -4 y = 5 8(2) - 4(5) = -2 -2 = -2 4(5) = 3(2) + 14 20 = 20 The solution is the point (2,5). Substitute (2,5) into both equations to check.
4x – 3y = 5 -2x + 3y = -7 7x – 2y = 5 7x – 3y = 4 On Your Own 3x + 4y = -6 2y = 3x + 6 (-1, -3) (1,1) (-2,0)
“Solve Linear Systems by Elimination Multiplying First!!” Multiply First Eliminated 6x + 5y = 19 6x + 5y = 19 Equation 1 x (-3) + -6x – 9y = -15 2x + 3y = 5 Equation 2 -4y = 4 y = -1 2x + 3y = 5 Equation 2 Substitute value for y into either of the original equations 2x + 3(-1) = 5 2x - 3 = 5 x = 4 6(4) + 5(-1) = 19 19 = 19 2(4) + 3(-1) = 5 5 = 5 The solution is the point (4,-1). Substitute (4,-1) into both equations to check.
“Solve Linear Systems by Elimination Multiplying First!!” Multiply First Eliminated x (-2) 2x + 5y = 3 -4x - 10y = -6 Equation 1 + 3x + 10y = -3 3x + 10y = -3 Equation 2 -x = -9 x = 9 2x + 5y = 3 Equation 1 Substitute value for x into either of the original equations 2(9) + 5y = 3 18 + 5y = 3 y = -3 2(9) + 5(-3) = 3 3 = 3 3(9) + 10(-3) = -3 -3 = -3 The solution is the point (9,-3). Substitute (9,-3) into both equations to check.
“Solve Linear Systems by Elimination Multiplying First!!” Multiply First Eliminated x (2) 4x + 5y = 35 8x + 10y = 70 Equation 1 + x (-5) 15x - 10y = 45 -3x + 2y = -9 Equation 2 23x = 115 x = 5 4x + 5y = 35 Equation 1 Substitute value for x into either of the original equations 4(5) + 5y = 35 20 + 5y = 35 y = 3 4(5) + 5(3) = 35 35 = 35 -3(5) + 2(3) = -9 -9 = -9 The solution is the point (5,3). Substitute (5,3) into both equations to check.
“Solve Linear Systems by Elimination Multiplying First!!” Multiply First Eliminated x (2) 9x + 2y = 39 18x + 4y = 78 Equation 1 + x (-3) -18x - 39y = 27 6x + 13y = -9 Equation 2 -35y = 105 y = -3 9x + 2y = 39 Equation 1 Substitute value for y into either of the original equations 9x + 2(-3) = 39 9x - 6 = 39 x = 5 9(5) + 2(-3) = 39 39 = 39 6(5) + 13(-3) = -9 -9 = -9 The solution is the point (5,-3). Substitute (5,-3) into both equations to check.
x + y = 2 2x + 7y = 9 6x – 2y = 1 -2x + 3y = -5 Guided Practice (1,1) (-0.5, -2) 3x - 7y = 5 9y = 5x + 5 (-10,-5)
A business with two locations buys seven large delivery vans and five small delivery vans. Location A receives five large vans and two small vans for a total cost of $235,000. Location B receives two large vans and three small vans for a total cost of $160,000. What is the cost of each type of van? 2x + 5y = 235,000 x = 3x + 2y = 160,000 y = (30,000, 35,000) $30,000 for a small van and $35,000 for a large van.
Homework PARCC prep • Text p. 251, #4-22 evens, 31