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Homework Assignment. Chapter 1, Problems 6, 15 Chapter 2, Problems 6, 8, 9, 12 Chapter 3, Problems 4, 6, 15 Chapter 4, Problem 16 Due a week from Friday: Sept. 22, 12 noon. Your TA will tell you where to hand these in. Random Sampling - what did we learn?. It’s difficult to do properly
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Homework Assignment • Chapter 1, Problems 6, 15 • Chapter 2, Problems 6, 8, 9, 12 • Chapter 3, Problems 4, 6, 15 • Chapter 4, Problem 16 • Due a week from Friday: • Sept. 22, 12 noon. • Your TA will tell you where to hand these in
Random Sampling - what did we learn? • It’s difficult to do properly • Why not just point? • Computers and random numbers • Can you tell if your numbers were random?
Sampling distribution of the mean How confident can we be about this one estimate of the mean?
Estimating error of the mean • Hard method: take a few MORE random samples, and get more estimates for the mean • Easy method: use the formula:
Confidence interval • Confidence interval • a range of values surrounding the sample estimate that is likely to contain the population parameter • We are 95% confident that the true mean lies in this interval
= 5.14 Y = 5.26
What if we calculate 95% confidence intervals? • Approximately ± 2 S.E. • Expect that 95% of the intervals from the class will contain the true population mean, 5.14 • 70 invervals * 5% = 3.5 • Expect that 3 or 4 will not contain the mean, and the rest will
Probability • The proportion of times the event occurs if we repeat a random trial over and over again under the same conditions • Pr[A] • The probability of event A
Mutually exclusive Venn diagram
Mutually exclusive Sample space Venn diagram
Mutually exclusive Sample space Possible outcome Pr[B] proportional to area Venn diagram
Mutually exclusive Pr(A and B) = 0
Mutually exclusive Visual definition - areas do not overlap in Venn diagram
Not mutually exclusive Pr(A and B) 0 Pr(purple AND square) 0
Probability distribution Random variable - a measurement that changes from one observation to the next because of chance
Probability distribution for the outcome of a roll of a die Frequency Number rolled
Probability distribution for the sum of a roll of two dice Frequency Sum of two dice
Addition Rule Pr[1 or 2] = ?
Addition Rule Pr[1 or 2] = Pr[1]+Pr[2]
Addition Rule Pr[1 or 2] = Pr[1]+Pr[2]
Addition Rule Sum of areas Pr[1 or 2] = Pr[1]+Pr[2]
The probability of a range For families of 8 children, Pr[Number of boys ≥ 6] = ?
The probability of a range For families of 8 children, Pr[Number of boys ≥ 6] = Pr[6 or 7 or 8] = Pr[6]+Pr[7]+Pr[8]
Addition Rule Pr[1 or 2 or 3 or 4 or 5 or 6] = ?
Addition Rule Pr[1 or 2 or 3 or 4 or 5 or 6] = 1
Probability of Not Pr[NOT rolling a 2] = ?
Probability of Not Pr[NOT rolling a 2] = 1 - Pr[2] = 5/6
Probability of Not Pr[NOT rolling a 2] = 1 - Pr[2] = 5/6 Pr[not A] = 1-Pr[A]
The addition rule What if they are not mutually exclusive?