Review

1. Review • Short range force, Pauli Principle  Shell structure, magic numbers, concept of valence nucleons • Residual interactions  favoring of 0+ coupling: 0+ ground states for all even-even nuclei • Concept of seniority  lowest states have low seniority, huge simplification (n-body calculations often reduce to 2-body !) •  constant g factors, constant energies in singly magic or near magic nuclei, parabolic B(E2) systematics, change in sign of quadrupole moments (prolate-oblate shapes) across a shell

2. Effects of monopole interactions Between 40Zr and 50Sn protons fill 1g9/2 orbit. Large spatial overlap with neutron 1g7/2 orbit. 1g7/2 orbit more tightly bound. Lower energy

3. Lecture 3Collective behavior in nuclei and collective models

4. How does structure evolve? • Benchmarks • Magic nuclei – spherical, stiff • Nuclei with only one kind of valence nucleon: like the 2-particle case • Nuclei with both valence protons and neutrons: mixing of configurations, complex wave functions with components from every configuration (~10big). • Is there another way? YES !!! • Macroscopic perspective. Many-body approach, collective coordinates, modes

5. Microscopic origins of collectivity correlations, configuration mixing and deformation: Residual interactions Crucial for structure

6. J = 2, one phonon vibration

7. More than one phonon? What angular momenta? M-scheme for bosons

9. Deformed Nuclei • What is different about non-spherical nuclei? • They can ROTATE !!! • They can also vibrate • For axially symmetric deformed nuclei there are two low lying vibrational modes called b gand g • So, levels of deformed nuclei consist of the ground state, and vibrational states, with rotational sequences of states (rotational bands) built on top of them.

10. 8+ 6+ 4+ 2+ 0+ Rotational Motion in nuclei E(I)  (ħ2/2I )J(J+1) R4/2= 3.33

11. Paradigm Benchmark 700 333 100 0 Rotor J(J + 1) Amplifies structural differences Centrifugal stretching Deviations 6+690 4+330 2+100 0+0 JE (keV) Identify additional degrees of freedom The value of paradigms ? Interpretation without rotor paradigm Exp.

12. 8+ 6+ 4+ 2+ 0+ Rotational states built on (superposed on) vibrational modes Vibrational excitations Rotational states Ground or equilibrium state

13. Systematics and collectivity of the lowest vibrational modes in deformed nuclei Notice that the the b mode is at higher energies (~ 1.5 times the g vibration near mid-shell)* and fluctuates more. This points to lower collectivity of the b vibration. * Remember for later !

15. How can we understand collective behavior • Do microscopic calculations, in the Shell Model or its modern versions, such as with density functional theory or Monte Carlo methods. These approaches are making amazing progress in the last few years. Nevertheless, they often do not give an intuitive feeling for the structure calculated. • Collective models, which focus not on the particles but the structure and symmetries of the many-body, macroscopic system itself. They are not predictive in the same way as microscopic calculations but they can reveal coherent behavior more clearly in many cases. • We will illustrate collective models with the IBA, historically, by far the most successful and parameter-efficient collective model.

16. IBA – A Review and Practical Tutorial F. Iachello and A. Arima • Drastic simplification of • shell model • Valence nucleons • Only certain configurations • Simple Hamiltonian – interactions • “Boson” model because it treats nucleons in pairs • 2 fermions boson

17. Shell Model Configurations Fermion configurations Roughly, gazillions !! Need to simplify The IBA Boson configurations (by considering only configurations of pairs of fermions with J = 0 or 2.)

18. Why s, d bosons? Lowest state of all e-e First excited state in non-magic s nuclei is 0+ d e-e nuclei almost always 2+  - fct gives 0+ ground state  - fct gives 2+ next above 0+

19. Modeling a Nucleus 3 x 1014 2+ states 2. Fermions → bosons J = 0 (s bosons) J = 2 (d bosons) IBA: 26 2+ states Why the IBA is the best thing since jackets 154Sm Shell model Need to truncate IBA assumptions Is it conceivable that these 26 basis states are correctly chosen to account for the properties of the low lying collective states? 1. Only valence nucleons

20. Note key point: Bosons in IBA are pairs of fermions in valence shell Number of bosons for a given nucleus is a fixednumber  N=6 5 =NNB= 11 Basically the IBA is a Hamiltonian written in terms of s and d bosons and their interactions. It is written in terms of boson creation and destruction operators. Let’s briefly review their key properties.

21. Review of phonon creation and destruction operators • What is a creation operator? Why useful? • Bookkeeping – makes calculations very simple. • B) “Ignorance operator”: We don’t know the structure of a phonon but, for many predictions, we don’t need to know its microscopic basis. is a b-phonon number operator. For the IBA a boson is the same as a phonon – think of it as a collective excitation with ang. mom. 0 (s) or 2 (d).

22. IBAhas a deep relation to Group theory That relation is based on the operators that create, destroy s and d bosons s†, s, d†,d operators Ang. Mom. 2 d† , d = 2, 1, 0, -1, -2 Hamiltonian is written in terms of s, d operators Since boson number is conserved for a given nucleus, H can only contain “bilinear” terms: 36 of them. Gr. Theor. classification of Hamiltonian Group is called U(6) s†s, s†d, d†s, d†d

23. Brief, simple, trip into the Group Theory of the IBA Next 8 slides give an introduction to the Group Theory relevant to the IBA. If the discussion of these is too difficult or too fast, don’t worry, you will be able to understand the rest anyway. Just take a nap for 5 minutes. In any case, you will have these slides on the web and can look at them later in more detail if you want. DON’T BE SCARED You do not need to understand all the details but try to get the idea of the relation of groups to degeneracies of levels and quantum numbers A more intuitive name for this application of Group Theory is “Spectrum Generating Algebras”

24. ex: e.g: or: Concepts of group theory First, some fancy words with simple meanings:Generators, Casimirs, Representations, conserved quantum numbers, degeneracy splitting Generatorsof a group: Set of operators , Oi that close on commutation. [ Oi , Oj] = OiOj - OjOi = Ok i.e., their commutator gives back 0 or a member of the set For IBA, the 36 operators s†s, d†s, s†d, d†d are generators of the group U(6). Generators:define and conserve some quantum number. Ex.: 36 Ops of IBA all conserve total boson number = ns+ nd N = s†s + d† Casimir:Operator that commutes with all the generators of a group. Therefore, its eigenstates have a specific value of the q.# of that group. The energies are defined solely in terms of that q. #. N is Casimir of U(6). Representations of a group: The set of degenerate states with that value of the q. #. A Hamiltonian written solely in terms of Casimirs can be solved analytically

25. Sub-groups: Subsets of generators that commute among themselves. e.g: d†d 25 generators—span U(5) They conserve nd (# d bosons) Set of states with same nd are the representations of the group [ U(5)] Summary to here: Generators: commute, define a q. #, conserve that q. # Casimir Ops: commute with a set of generators  Conserve that quantum # A Hamiltonian that can be written in terms of Casimir Operators is then diagonal for states with that quantum # Eigenvalues can then be written ANALYTICALLY as a function of that quantum #

26. Simple example of dynamical symmetries, group chain, degeneracies [H, J2] = [H, JZ] = 0 J, M constants of motion

27. Let’s illustrate group chains and degeneracy-breaking. Consider a Hamiltonian that is a function ONLY of: s†s + d†d That is: H = a(s†s + d†d) = a (ns + nd ) = aN In H, the energies depend ONLY on the total number of bosons, that is, on the total number of valence nucleons. ALL the states with a given N are degenerate. That is, since a given nucleus has a given number of bosons, if H were the total Hamiltonian, then all the levels of the nucleus would be degenerate. This is not very realistic (!!!) and suggests that we should add more terms to the Hamiltonian. I use this example though to illustrate the idea of successive steps of degeneracy breaking being related to different groups and the quantum numbers they conserve. The states with given N are a “representation” of the group U(6) with the quantum number N. U(6) has OTHER representations, corresponding to OTHER values of N, but THOSE states are in DIFFERENT NUCLEI (numbers of valence nucleons).

28. H’ = H + b d†d = aN + b nd Now, add a term to this Hamiltonian: Now the energies depend not only on N but also on nd States of a given nd are now degenerate. They are “representations” of the group U(5). States with different nd are not degenerate

29. H’ = aN + b d†d = a N + b nd N + 2 2a N + 1 a 2 2b Etc. with further terms 1 b N 0 0 0 nd E U(6) U(5) H’ = aN + b d†d

30. Concept of a Dynamical Symmetry OK, here’s the key point : N Spectrum generating algebra !!

31. OK, here’s what you need to remember from the Group Theory Group Chain: U(6)  U(5)  O(5) O(3) A dynamical symmetry corresponds to a certain structure/shape of a nucleus and its characteristic excitations. The IBA has three dynamical symmetries: U(5), SU(3), and O(6). Each term in a group chain representing a dynamical symmetry gives the next level of degeneracy breaking. Each term introduces a new quantum number that describes what is different about the levels. These quantum numbers then appear in the expression for the energies, in selection rules for transitions, and in the magnitudes of transition rates.

32. Group Structure of the IBA U(5) vibrator U(6) SU(3) rotor O(6) γ-soft 1 s boson : 5 d boson : Magical group theory stuff happens here Symmetry Triangle of the IBA Def. Sph.

33. IBA Hamiltonian Counts the number of d bosons out of N bosons, total. The rest are s-bosons: with Es = 0 since we deal only with excitation energies. Excitation energies depend ONLY on the number of d-bosons. E(0) = 0, E(1) = ε , E(2) = 2 ε. Conserves the number of d bosons. Gives terms in the Hamiltonian where the energies of configurations of 2 d bosons depend on their total combined angular momentum. Allows for anharmonicities in the phonon multiplets. d+d d Mixes d and s components of the wave functions Most general IBA Hamiltonian in terms with up to four boson operators (given N)

34. U(5)Spherical, vibrational nuclei

35. Simplest Possible IBA Hamiltonian – given by energies of the bosons with NO interactions 3 2 1 0 nd 6+, 4+, 3+, 2+, 0+ 4+, 2+, 0+ 2+ 0+ = E of d bosons + E of s bosons Excitation energies so, set s = 0, and drop subscript d on d What is spectrum? Equally spaced levels defined by number of d bosons What J’s? M-scheme Look familiar? Same as quadrupole vibrator. U(5) also includes anharmonic spectra

36. E2 Transitions in the IBA Key to most tests Very sensitive to structure E2 Operator: Creates or destroys an s or d boson or recouples two d bosons. Must conserve N T = e Q = e[s† + d†s + χ (d† )(2)] Specifies relative strength of this term

37. 3 2 1 0 nd 6+, 4+, 3+, 2+, 0+ 4+, 2+, 0+ 2+ 0+ E2 transitions in U(5) • χ = 0 so • T = e[s† + d†s] • Can create or destroy a single d boson, that is a single phonon.

38. Vibrator Vibrator (H.O.) E(I) = n (0 ) R4/2= 2.0 8+. . . 6+. . . 2+ 0+

39. IBA Hamiltonian Complicated and not really necessary to use all these terms and all 6 parameters Simpler form with just two parameters – RE-GROUP TERMS ABOVE H =ε nd -  Q  Q Q = e[s† + d†s + χ (d† )(2)] Competition:ε nd term gives vibrator.  Q  Qterm gives deformed nuclei. This is the form we will use from here on

40. Relation of IBA Hamiltonian to Group Structure We will see later that this same Hamiltonian allows us to calculate the properties of a nucleus ANYWHERE in the triangle simply by choosing appropriate values of the parameters

41. SU(3)Deformed nuclei

42.   M

43. Typical SU(3) Scheme • Characteristic signatures: • Degenerate bands within a group • Vanishing B(E2) values between groups • Allowed transitions • between bands within a group • Where? N~ 1-4, Yb, Hf SU(3)  O(3) K bands in (, ) : K = 0, 2, 4, - - - - 

44. Totally typical example Similar in many ways to SU(3). But note that the two excited excitations are not degenerate as they should be in SU(3). While SU(3) describes an axially symmetric rotor, not all rotors are described by SU(3) – see later discussion

46. Mid-shell B(E2) N2 ~N N Example of finite boson number effects in the IBA B(E2: 2 0): U(5) ~ N; SU(3) ~ N(2N + 3) ~ N2 H =ε nd -  Q  Q and keep the parameters constant. What do you predict for this B(E2) value?? !!!

47. O(6)Axially asymmetric nuclei(gamma-soft)

50. Note: Uses χ = o