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Chapter 10. Quadratic Relations. In this chapter you should …. Learn to write and graph the equation of a circle. Learn to find the center and radius of a circle and use it to graph the circle. Conics. Definition: A conic section is the intersection of a plane and a cone.
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Chapter 10 Quadratic Relations
In this chapter you should … • Learn to write and graph the equation of a circle. • Learn to find the center and radius of a circle and use it to graph the circle .
Conics Definition:A conic section is the intersection of a plane and a cone. By changing the angle and location of intersection, we can produce a circle, ellipse, parabola or hyperbola; or in the special case when the plane touches the vertex: a point, line or 2 intersecting lines. Circle Ellipse Parabola Hyperbola
Graphing Conics • x2 + y2 = 25 • 9x2 + 16y2 = 144 • x2 - y2 = 9
What am I ?? • x2 - 2y2 = 4 • 6x2 + 6y2 = 600 • 4x2 + 25y2 = 100
Parabolas Vertex form: y = a(x – h)2 + k where the vertex is (h, k). If a is negative, the parabola opens down. If a is positive, the parabola opens up. If is greater than 1, the parabola is tall & skinny. If is less than 1, the parabola is short & fat. If is equal to 1, the parabola is average. Notice for the vertex that the sign of “h” is opposite its sign in the parentheses.
y = -2 (x – 5)2 + 3 y = ¼ (x + 3)2 - 9 vertex: ( , ) opens: shape: vertex: ( , ) opens: shape: Examples for parabolas
y = -x2 – 10 y = (x+5)2 vertex: ( , ) opens: shape: vertex: ( , ) opens: shape: More examples for parabolas
Graphing Parabolas • Remember that a vertical line, the “axis of symmetry”, goes through the vertex. Points on each side of this line are reflections: they will have the same y-coordinate. • To graph a parabola, first graph the vertex and lightly sketch the axis of symmetry. Consider whether the parabola opens up or down. • Choose an x just to the right or left of the vertex. Find the y-value and graph the point, then graph its reflection across the axis of symmetry. Repeat with another point.
Example of graphing • Graph y = 2(x + 3)2 – 5 • vertex: ( -3, -5) • opens: upward • axis of symmetry: x = -3 • complete: (-2, _____) and reflection (___, ___) • complete: (-1, _____) and reflection (___, ___)
Graphing Practice • graph y = ½(x – 2)2 – 4 • graph y = -2(x – 5)2 • graph y = -(x+3)2 + 6
Writing in Vertex Form • An equation of a parabola in quadratic form: y = ax2 + bx + c How will you graph it if it’s not in vertex form? Find the vertex the way you did in Chapter 5! The x-coordinate of the vertex is on the axis of symmetry: Find the value of (x, y) at the vertex. This is now (h, k). Get the value of “a” from the x2 term. Now write the equation in the form y = a( x – h)2 + k.
Practice with vertex form • Write y = 2x2 + 20x + 53 in vertex form. Find the vertex, axis of symmetry, direction of opening; graph. • vertex: x = = -5. y = 2(-5)2 + 20(-5) + 53 = 3. vertex: (-5, 3); axis of symmetry: x = -5. • a = 2 (coefficient of x2); parabola opens • upward. • vertex form of equation: y = 2(x + 5)2 + 3
y = 2x2 – 12x + 9 y = 1/2x2 + 2x – 8 y = -x2 + 2x + 1 y = -6x2 – 12x - 1 Answers y = 2(x – 3)2 – 9 y = ½(x + 2)2 – 10 y = -(x – 1)2 + 2 y = -6( x + 1)2 + 5 Practice vertex form with these
Graphing Now, can you graph those four problems? Remember the steps: • axis of symmetry (h) • vertex (h, k) • direction of opening (a) • a couple of points & their reflections
Solving Quadratic Systems Method 1: Solve the system algebraically: • Subtract the like terms to eliminate the x2 terms • Solve for y. Substitute your answer to get the value of x. • You might get more than one y; if so, you also get more than one x. Your answer would have two (x, y) solutions.
Method 2: Solve the system graphically • Re-write each equation in terms of y = .... • Remember the there are two square roots of y2: and . • Graph each of the equations and find their points of intersection, using the graphing calculator.
What you’ll learn … Learn to write and graph the equation of a circle. Learn to find the center and radius of a circle and use it to graph the circle 10-3 Circles 2.09 Use the equations of parabolas and circles to model and solve problems. a) Solve using tables, graphs, and algebraic properties. b) Interpret the constants and coefficients in the context of the problem.
A circle is the set of all points in a plane that are distance r from a given point, called the center. The distance r is called the radius. • If r is the radius of a circle with a center at the origin, then the equation of the circle can be written in the form x2 + y2 = R2
Memorize this!!! The Standard Form of the Equation of a Circle (h, k) is the centerr is the radius(x, y) is any point on the circle
Write an equation of a circle with center (-4,3) and radius 4. Example 1 Writing an Equation of a Circle Write an equation of a circle with center (5,-2) and radius 8.
Write an equation for the translation of x2 + y2 =9 four units left and three units up. Then graph the translation. Example 2a Using Translations to Write an Equation
Write an equation for the translation of x2 + y2 =1 nine units right and two units down. Then graph the translation. Example 2a Using Translations to Write an Equation
Find the center and radius of the circle with equation (x – 16)2 + (y +9)2 = 144. Example 4 Finding the Center and Radius Find the center and radius of the circle with equation (x + 8)2 + (y +3)2 = 121.
Find the center and radius of the circle with equation x2 + y2 – 8x - 4y + 19 = 0. Example 4b Finding the Center and Radius Find the center and radius of the circle with equation x2 + y2 + 6y - 27 = 0.
Find the center and radius of the circle with equation x2 – 10x + y2 + 4y - 7 = 0. Example 4c Finding the Center and Radius Find the center and radius of the circle with equation x2 + 2x + y2 - 10y - 38 = 0.
Graph (x + 1)2 + (y – 3)2 = 25 Example 5 Graphing a Circle using Center and Radius Graph (x - 4)2 + (y + 2)2 = 49
In this chapter you should have … • Learned to write and graph the equation of a circle. • Learned to find the center and radius of a circle and use it to graph the circle .