160 likes | 281 Views
AP Calculus BC Monday, 21 October 2013. OBJECTIVE TSW will review for tomorrow’s test over sec. 3.1 – 3.4. ASSIGNMENTS DUE TOMORROW Sec. 3.3 Sec. 3.4. Sec. 3.4: p. 196 (49-56 all) ANSWERS. Sec. 3.4: p. 196 (49-56 all) ANSWERS. x -intercepts. no holes/asymptotes. ↓: ( −∞, 3). cusp.
E N D
AP Calculus BCMonday, 21 October 2013 • OBJECTIVETSW will review for tomorrow’s test over sec. 3.1 – 3.4. • ASSIGNMENTS DUE TOMORROW • Sec. 3.3 • Sec. 3.4
Sec. 3.4: p. 196 (49-56 all) ANSWERS x-intercepts no holes/asymptotes ↓: (−∞, 3) cusp ↑: (3, ∞) CD: (−∞, 3) ᴜ (3, ∞) x-intercepts ↑: (−∞, 1) horizontal tangent ↓: (1, ∞) CD: (−∞, ∞)
AP Calculus BCTEST TOPICS: Sec. 3.1 – 3.4 CALCULATOR • Locate absolute extrema of a function on a closed interval. • Verify and apply Rolle's Theorem. • Apply the Mean Value Theorem. • Find relative extrema, increasing/decreasing intervals, points of inflection, and intervals of concavity. • First Derivative Test. • Second Derivative Test.
AP Calculus BCTEST TOPICS: Sec. 3.1 – 3.4 NON-CALCULATOR • Determine relative extrema. • First Derivative Test (with a sign graph) • Second Derivative Test • Determine increasing/decreasing intervals from a sign graph of the 1st derivative. • Determine points of inflection, and intervals of concavity from a sign graph of the 2nd derivative.
AP Calculus BCTEST TOPICS: Sec. 3.1 – 3.4 NON-CALCULATOR • From the graph of a function, draw graphs of its first and second derivatives. • Sec. 3.4: p. 196 (49-52) • Construct a graph from given characteristics. • Sec. 3.4: p. 196 (53-56)
AP Calculus BCTEST TOPICS: Sec. 3.1 – 3.4 • The first part of the test will be with a calculator; the second part will be without. • Study notes, assignments, and Power Points. • Wear a purple JVHS shirt!!! • Questions?
QUIZ: Sec. 3.1 – 3.3 Absolute max.: (1, –1) Absolute min.: (–1, –5)
QUIZ: Sec. 3.1 – 3.3 b) i. f is continuous on [0, 4] ii. f is differentiable on (0, 4) iii. f (0) = f (4) = –5 Rolle’s Theorem may be applied.
QUIZ: Sec. 3.1 – 3.3 a) i. f is continuous on [–1, 1] ii. f is differentiable on (–1, 1) The MVT may be applied.
QUIZ: Sec. 3.1 – 3.3 b) c)
QUIZ: Sec. 3.1 – 3.3 a) b) c)