1 / 32

Course 1

Course 1. Multiplication Equations. 2-7. Warm Up. Problem of the Day. Lesson Presentation. Course 1. 130. 60. 91. 72. 65. 40. 12. 10. 6. 5. 5. 7. Warm Up Divide. 1. 2. 3. 4. 5. 6. 6. 13. 10. 4. 26. 13. Problem of the Day

metta
Download Presentation

Course 1

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Course 1 Multiplication Equations 2-7 Warm Up Problem of the Day Lesson Presentation Course 1

  2. 130 60 91 72 65 40 12 10 6 5 5 7 Warm Up Divide. 1. 2. 3. 4. 5. 6. 6 13 10 4 26 13

  3. Problem of the Day Katie’s little brother is building a tower with blocks. He adds 6 blocks and then removes 4 blocks. If he adds 8 more blocks, the tower will have twice as many blocks as when he started. How many blocks did he start with? 10 blocks

  4. Learn to solve whole-number multiplication equations.

  5. 4 4 Division is the inverse of multiplication. To solve an equation that contains multiplication, use division to “undo” the multiplication. 4m = 32 Caution ! 4m = 32 4m means “4  m.” m = 8

  6. 5 5 ? 5(15)= 75 ? 75 = 75 Additional Example 1A: Solving Multiplication Equations Solve the equation. Check your answer. 5p = 75 p is multiplied by 5. Divide both sides by 5 to undo the multiplication. 5p = 75 p = 15 Check 5p = 75 Substitute 15 forp in the equation.  15 is the solution.

  7. 8 8 ? 16 = 8(2) ? 16 = 16 Additional Example 1B: Solving Multiplication Equations Solve the equation. Check your answer. 16 = 8r r is multiplied by 8. 16 = 8r Divide both sides by 8 to undo the multiplication. 2 = r Check 16 =8r Substitute 2 forr in the equation.  2 is the solution.

  8. 8 8 ? 8(9)= 72 ? 72 = 72 Check It Out: Example 1A Solve the equation. Check your answer. a is multiplied by 8. 8a = 72 8a = 72 Divide both sides by 8 to undo the multiplication. x = 9 Check 8a = 72 Substitute 9 fora in the equation.  9 is the solution.

  9. 3 3 ? 18 = 3(6) ? 18 = 18 Check It Out: Example 1B Solve the equation. Check your answer. w is multiplied by 3. 18 = 3w 18 = 3w Divide both sides by 3 to undo the multiplication. 6 = w Check 18 =3w Substitute 6 forw in the equation.  6 is the solution.

  10. Additional Example 2: Problem Solving Application The area of a rectangle is 56 square inches. Its length is 8 inches. What is its width?

  11. 1 Understand the Problem Additional Example 2 Continued The answer will be the width of the rectangle in inches. List the important information: • The area of the rectangle is 56 square inches. • The length of the rectangle is 8 inches. Draw a diagram to represent this information. w 56 8

  12. Make a Plan 2 Additional Example 2 Continued You can write and solve an equation using the formula for area. To find the area of a rectangle, multiply its length by its width. A= lw w 56 = 8w l

  13. 3 Solve 8 8 Additional Example 2 Continued 56= 8w w is multiplied by 8. 56= 8w Divide both sides by 8 to undo the multiplication. 7= w So the width of the rectangle is 7 inches.

  14. 4 Additional Example 2 Continued Look Back Arrange 56 identical squares in a rectangle. The length is 8, so line up the squares in rows of 8. You can make 7 rows of 8, so the width of the rectangle is 7.

  15. Check It Out: Example 2 The area of a rectangle is 48 square inches. Its width is 8 inches. What is its length?

  16. 1 Understand the Problem Check It Out: Example 2 The answer will be the length of the rectangle in inches. List the important information: • The area of the rectangle is 48 square inches. • The width of the rectangle is 8 inches. Draw a diagram to represent this information. 8 48 l

  17. Make a Plan 2 Check It Out: Example 2 Continued You can write and solve an equation using the formula for area. To find the area of a rectangle, multiply its length by its width. A= lw w 48 = l8 l

  18. 3 Solve 8 8 Check It Out: Example 2 Continued 48= 8l l is multiplied by 8. 48= 8l Divide both sides by 8 to undo the multiplication. 6= l So the length of the rectangle is 6 inches.

  19. 4 Check It Out: Example 2 Continued Look Back Arrange 48 identical squares in a rectangle. The width is 8, so line up the squares in columns of 8. You can make 6 columns of 8, so the length of the rectangle is 6.

  20. Lesson Quiz y = 30 1. 10y = 300 2. 2y = 82 3. 63 = 9y 4. 78 = 13x y = 41 y = 7 x = 6 5. The area of a board game is 468 square inches. Its width is 18 inches. What is the length? 26 inches

  21. Course 1 Division Equations 2-8 Warm Up Problem of the Day Lesson Presentation Course 1

  22. Division Equations 2-8 Course 1 Warm Up Solve. 1. 5x = 20 2.7n = 84 3. 18 = y – 4 4. 21 = n + 3 x = 4 n = 12 y = 22 n = 18 Course 1

  23. Problem of the Day If 11 is 4 less than 3 times a number, what is the number? 5

  24. Learn to solve whole-number division equations.

  25. Multiplication is the inverse of division. When an equation contains division, use multiplication to “undo” the division.

  26. 35 x x x = 5 = 5 = 5 = 5 7 7 7 7 x is divided by 7. x 7 = 7 5 7 Check ? ? 5 = 5 Additional Example 1A: Solving Division Equations Solve the equation. Check your answer. Multiply both sides by 7 to undo the division. x = 35 Substitute 35 for x in the equation. 35 is the solution. 

  27. 78 p p p 13 = 13 = 13 = 13 = 6 6 6 6 p is divided by 6. p 6 13 = 6 6 Check ? ? 13 = 13 Additional Example 1B: Solving Division Equations Solve the equation. Check your answer. Multiply both sides by 6 to undo the division. 78 = p Substitute 78 for p in the equation. 78 is the solution. 

  28. 18 x x x = 9 = 9 = 9 = 9 2 2 2 2 x is divided by 2. x 2 = 2 9 2 Check ? ? 9 = 9 Check It Out: Example 1A Solve the equation. Check your answer. Multiply both sides by 2 to undo the division. x = 18 Substitute 18 for x in the equation. 18 is the solution. 

  29. p p p 72 = 72 = 72 = 4 4 4 p is divided by 4. p 4 72 = 4 4 Check 288 ? 72 = 4 ? 72 = 72 Check It Out: Example 1B Solve the equation. Check your answer. Multiply both sides by 4 to undo the division. 288 = p Substitute 288 for p in the equation. 288 is the solution. 

  30. h 3 14 = 3 3 h Substitute 14 for height of aspen. h is divided by 3. 14 = 3 Additional Example 2: Application At Elk Meadows Park an aspen tree is one-third the height of a pine tree. height of pine height of aspen = 3 The aspen tree is 14 feet tall. How tall is the pine tree? Let h represent the height of the pine tree. Multiply both sides by 3 to undo the division. 42 = h The pine tree is 42 feet tall.

  31. w 95 = 2 Substitute 95 for Jamie’s weight. w is divided by 2. w 2 2 95 = 2 Check It Out: Example 2 Jamie weighs one-half as much as her father. father’s weight Jamie’s weight = 2 Jamie weighs 95 pounds. How many pounds does her father weigh? Let w represent her father’s weight. Multiply both sides by 2 to undo the division. 190 = w Jamie’s father weighs 190 pounds.

  32. x x x x 10 15 4 9 Lesson Quiz Solve each equation. Check your answers. 1. = 7 2. 8 = 3. = 11 4. = 7 x = 70 x = 32 x = 99 x = 105 5. The area of Sherry’s flower garden is one- fourth the area of her vegetable garden. The area of the flower garden is 17 square feet. Let x represent the area of her vegetable garden. Find the area of her vegetable garden? 68 square feet

More Related