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Experience Calculus from Daily Life. Making Maths Visible by Sunil Bajaj, Sr. Specialist SCERT, Haryana, Sohna Road Gurgaon. Mathematics continues to draw reverence and fear in equal measure across generations.
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Experience Calculus from Daily Life Making Maths Visible by Sunil Bajaj, Sr. Specialist SCERT, Haryana, Sohna Road Gurgaon
Mathematics continues to draw reverence and fear in equal measure across generations. • Students studying in school seldom get opportunity to “experience” the subject.
Experience Calculus from Daily Life Can we make a change by relating it to Daily Life? Let us try
Experience Calculus from Daily Life • The seminal objective of this is to make the Maths concepts “visible” by ‘abstract concepts’ into a ‘concrete manifestations • Need of the concepts and their use in daily life
Starting Point With the Calculus as a key, Mathematics can be successfully applied to the explanation of the course of Nature.” — WHITEHEAD
Function Take a cylindrical vessel of certain volume. volume of liquid in cylinder is V = r2h( r is constant) Let radius= 10cm V = (10)2h orV=100h cm2 Now volume is a function of variable H (height ) which can be expressed as V=f(h) If H= 7cm Domain is [0,7] then Range is [0,2200]
Experience Calculus from Daily Life Derivative Rate of change speed
V= f(h) =volume of water in beaker V= f(h) = r2 h If r=K ( constant ) = K2 h
Rate of change of volume in beaker is r2 which is visible as oil drop spreads as of yellow color.
Derivative of V w.r.t. h =f’(h) =K2 Every drop is taking the shape of circular region of radius that of beaker with area K2
Volume of Cuboid Length and breadth are constant
Volume of cone tan α =r/h where α is semi vertical angle( constant ) Hence r = h tan α. If we differentiate V = with respect to h
Put r = h tan α. V = V = V
USE Computer use derivatives for a lot of signal processing algorithms. The stock market uses derivatives to see how stocks are changing. Anything that relates two values at different times most likely uses a derivative process.
Make open box of Maximum capacity V(x) = x (30 – 2x) (80 – 2x) = 4x3 – 220x2 + 2400x Putting V/(x) = 12x2 – 440x+ 2400=0 We get , x= 30,20/3 , reject 30 and take 20/3