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Ultraviolet Spectroscopy

Ultraviolet Spectroscopy. 紫外光谱. 9.1 Basics of Ultraviolet Spectroscopy.

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Ultraviolet Spectroscopy

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  1. Ultraviolet Spectroscopy 紫外光谱

  2. 9.1 Basics of Ultraviolet Spectroscopy • The UV involves the absorption of ultraviolet light by a molecule causing the promotion of an electron from a ground electronic state to an excited electronic state. The transitions are generally between a bonding or lone-pair orbital and an unfilled non-bonding or anti-bonding orbital. The wavelength of the absorption is then a measure of the separation of the energy levels of the orbitals concerned.

  3. UV UV-Vis * > n* >* > n* <200nm 200 to 800 nm

  4. 9.2 The UV-Vis spectrum and Beer’ laws • The UV-Vis spectrum typically represents the absorption of light as a plot (Figure 3.2) of energy (as wavelength, λ , in nanometers, from E = hc/λ) versus the intensity of absorption (as absorbance, A, or molar extinction coefficient, ε).

  5. Quantitative measurement (定量测定) (IR, UV-vis, AAS, etc.)

  6. 9.3 Instrumentation • Instrument: spectrophotometer(分光光度计) • Stimulus: monochromatic light energy(单色光) • Analytical response: light absorption • Transducer(传感器): photocell • Data: electrical current • Data processor处理器: current meter(测流计) • Readout: meter scale(仪表) photocell Current Meter Light Intensity Current Scale

  7. 动画(部件), P246

  8. 闪耀光栅 准直透镜 P247 动画grating and monochromator

  9. 仪器进展:

  10. 透镜 传感器、检测器 动画PMT 动画pee

  11. 动画(紫外) single beam (SB) double-beam (DB) double beam

  12. 9.4 Charge transfer transitions (P250) 电荷转移跃迁(荷移吸收光谱 ) 电荷转移跃迁本质上属于分子内氧化还原反应,因此呈现荷移光谱的必要条件是构成分子的二组分,一个为电子给予体,另一个应为电子接受体。

  13. A + D D+A- hv (受电子体)(给电子体) 血红色;490nm [Fe3+ SCN-]+h = [Fe2+SCN ]2+ 无色 六甲基苯 黄色 四氯苯醌 深红色

  14. c3 > c2 > c1 B A c3c2c1 λa λb   a 9.5 Applications:Foundamentalvariables • The wavelength (or energy) of the radiation.(辐射的波长;定性) ☆不同的物质只对不同的、特定波长的光有较强的吸收或发射。(other wavelength, transparent) • The amount of the radiation at .(辐射的强度;定量) ☆同一物质(溶液)不同浓度的吸收曲线

  15. Example 1(P7); Example 2 • Potassium dichromate(重铬酸盐) and potassium permanganate have overlapping absorption spectra in 1 M H2SO4. K2Cr2O7 has an absorption maximum at 440 nm, and KMnO4 has a band at 545 nm (the maximum is actually at 525 nm, but the longer wavelength is generally used where interference from K2Cr2O7 is less).

  16. A mixture is analyzed by measuring the absorbance at these two wavelengths with the following results: A440 = 0.405, A545 = 0.712 in a 1-cm cell (approximate; exact length not known). The absorbances of pure solutions of K2Cr2O7 (1.00 10-3 M) and KMnO4 (2.00  10-4 M) in 1 M H2SO4,

  17. using the same cell gave the following results: ACr,440 = 0.374, ACr,545 = 0.009, AMn,440 = 0.019, AMn,545 = 0.475. Calculate the concentrations of dichromate and permanganate in the sample solution.

  18. Interferences(干扰、影响因素) • Spectral interference(光谱干扰) matrix 基体,基质,样品; component 组成,组分 assay 特定的测定方法 • Chemical interference(化学干扰) • Instrument interference(仪器干扰)

  19. 缺点:吸收峰少 • 定性分析(qualitative analysis确定未知化合物) 定性鉴别的依据→吸收光谱的特征(反映结构中生色团和助色团的特性,不完全反映分子特性;甲苯与乙苯:谱图基本相同;) 吸收光谱的形状、吸收峰的数目、吸收峰的位置(波长)、吸收峰的强度、相应的吸光系数max;(比较法、标准谱图库) 借助经验规则计算吸收峰波长;

  20. 1.比较下列化合物(a, b, c)的最大吸收波长 2.IR表明化合物C9H10O分别含有一个苯环、羰基、亚甲基、甲基,但无法确定羰基的位置。UV显示有三个吸收带254nm(lgmax=4.1); 280nm(lgmax=3.1);320nm(lgmax =1.9)。化合物结构是?

  21. 3. 某化合物在200-400nm范围内没吸收,该化合物是芳香族;含共轭双键;醛;酮;羧酸 4. 某化合物分子式C5H8O,在UV图上有两个吸收带(224,9750;314,38),结构是 CH3CH=CHCOCH3;CH2=CHCH2COCH3 CH3CH=CHCH2CHO;CH2=CH(CH2)2CHO 5. 某羰基化合物在近紫外和可见光区只产生一个204nm (60)的弱吸收带。该化合物可能是酯;醛酮;,-不饱和醛酮;,-不饱和酯;

  22. 在下列化合物中同时含有*、 n*跃迁的化合物是 三氯甲烷、丙酮、丁二烯、二甲苯 • 在下列化合物中,那一个化合物能吸收波长较长的辐射( ) 苯、二甲苯、对氯代甲苯、萘 • 某化合物分子式为C9H10O, 其图如右,指出发色团。 ~320nm 230nm 270nm 360nm

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