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Multiplying monomial with binomial. Monomial An algebraic expression which contains only one term is known as Monomial Example : 2 x , 3 x 2 , 4t, 9p 2 q, -8mn 2. Multiply Monomials by Binomials Monomial is outside the parenthesis (bracket). Binomial is inside the parenthesis.
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Monomial An algebraic expression which contains only one term is known as Monomial Example : 2x, 3x2, 4t, 9p2q, -8mn2 • Multiply Monomials by Binomials • Monomial is outside the parenthesis (bracket). • Binomial is inside the parenthesis. • Use distributive property to open the parenthesis. • Distributive property --->Multiply each term of the parenthesis by the • monomial keeping the addition or subtraction sign same.
Example 1: Multiply 2a and (3a - 4) Solution: 2a Monomial 3a - 4 Binomial Write in the multiplication expression and we get: 2a x (3a - 4) Use Distributive Law and multiply monomial with every term of binomial & this is done in the following steps: = 2a x 3a – 2a x 4 = (2 x 3) (a x a) – (2 x 4) a = 6a2 – 8a x 2a x (3a - 4) Multiply the numerical coefficients and variables separately. x For variables, add the power of exponents, a x a = a1+1 = a2 (a = a1) Ans:2a x (3a – 4) = 6a2 – 8a
Example 2: Multiply (-3f) and (5f + f6) Solution: 5f + f6 -3f Monomial Binomial Write in the multiplication expression and we get: (-3f) x (5f + f6) Use Distributive Law and multiply monomial with every term of binomial & this is done in the following steps: (-3f) x (5f + f6) = (-3f) x 5f + (-3f) x f6 = (-3 x 5) (f x f) + (-3) (f x f6) = -15f2 – 3f7 Multiply the numerical coefficients and variables separately. x For variables, add the exponents, f x f = f1+1 = f2 (f = f1) f x f6 = f1+6 = f7 (f = f1) x Ans:(-3f) x (5f + f6) = -15f2 – 3f7
Example 3: Multiply 3ab and (a2b – ab2) Solution: 3ab Monomial a2b – ab2 Binomial Write in the multiplication expression and we get: 3ab x (a2b – ab2) Use Distributive Law and multiply monomial with every term of binomial & this is done in the following steps: Multiply variables with the base of a and b separately. = 3ab x a2b – 3ab x ab2 = 3 (a x a2) (b x b) – 3 (a x a) (b x b2) = 3a3b2 – 3a2b3 3ab x (a2b – ab2) x For variables, add the powers exponents, a x a2 = a1+2 = a3 (a = a1) b x b = b1+1 = b2 (b = b1) a x a = a1+1 = a2 (a = a1) b x b2 = b1+2 = b3 (b = b1) x Ans:3ab x (a2b – ab2) = 3a3b2 – 3a2b3
Try These Multiply (6b4) and (b+7) Multiply (-5h2) and (h5+7h)