1 / 10

The Distance and Midpoint Formulas

The Distance and Midpoint Formulas. p. 589. Geometry Review!. What is the difference between the symbols AB and AB?. Segment AB. The length of Segment AB. The Distance Formula. The Distance d between the points (x 1 ,y 1 ) and (x 2 ,y 2 ) is :. Find the distance between the two points. .

nevan
Download Presentation

The Distance and Midpoint Formulas

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. The Distance and Midpoint Formulas p. 589

  2. Geometry Review! • What is the difference between the symbols AB and AB? Segment AB The length of Segment AB

  3. The Distance Formula • The Distance d between the points (x1,y1) and (x2,y2) is :

  4. Find the distance between the two points. • (-2,5) and (3,-1) • Let (x1,y1) = (-2,5) and (x2,y2) = (3,-1)

  5. Classify the Triangle using the distance formula (as scalene, isosceles or equilateral) Because AB=BC the triangle is ISOSCELES

  6. The Midpoint Formula • The midpoint between the two points (x1,y1) and (x2,y2) is:

  7. Find the midpoint of the segment whose endpoints are (6,-2) & (2,-9)

  8. Write an equation in slope-intercept form for the perpendicular bisector of the segment whose endpoints are C(-2,1) and D(1,4). • First, find the midpoint of CD. (-1/2, 5/2) • Now, find the slope of CD. m=1 * Since the line we want is perpendicular to the given segment, we will use the opposite reciprocal slope for our equation.

  9. (y-y1)=m(x-x1) or y=mx+b Use (x1 ,y1)=(-1/2,5/2) and m=-1 (y-5/2)=-1(x+1/2) or 5/2=-1(-1/2)+b y-5/2=-x-1/2 or 5/2=1/2+b y=-x-1/2+5/2 or 5/2-1/2=b y=-x+2 or 2=b y=-x+2

  10. Assignment • 592 6-48 every third

More Related