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Reminder: Removing Brackets

Reminder: Removing Brackets. Multiplying Pairs of Brackets. Reminder: Removing Brackets. 2 × a. 2 × +3. 2(a + 3). + 6. = 2a. Reminder: Removing Brackets. 3 × b. 3 × -4. 3(b - 4). - 12. = 3b. Reminder: Removing Brackets. -4 × c. -4 × +2. -4(c + 2). - 8. = -4c. (x + 2).

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Reminder: Removing Brackets

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  1. Reminder: Removing Brackets Multiplying Pairs of Brackets

  2. Reminder: Removing Brackets 2 ×a 2 ×+3 2(a + 3) + 6 = 2a

  3. Reminder: Removing Brackets 3 ×b 3 ×-4 3(b - 4) - 12 = 3b

  4. Reminder: Removing Brackets -4 ×c -4 ×+2 -4(c + 2) - 8 = -4c

  5. (x + 2) (x + 3) Simplify: Calculating Areas x 3 The diagram opposite shows a large rectangle made up from smaller rectangles. The area of the large rectangle will be equal to its x x2 3x 2 2x 6 length × breadth. A = (x + 3)(x + 2) Giving: A = (x + 3)(x + 2) But the area will also equal the total area of the smaller rectangles. A = + + + A = x2 + 5x + 6

  6. (x + 2) (x + 3) Another Approach x 3 Instead of using four smaller areas, we could use two: x x(x + 2) 3(x + 2) 2 + A = A = x2 + 2x + 3x + 6 A = x2 + 5x + 6

  7. (x + 2) (x + 3) Another Approach x 3 So now we can see that x A = (x + 3)(x + 2) 2 A = x(x + 2) + 3(x + 2) A = x2 + 2x + 3x + 6 A = x2 + 5x + 6

  8. (x + 3) (x + 4) Example x 4 Follow a similar method to find the larger area. x Solution: A = (x + 4)(x + 3) 3 A = x(x + 3) + 4(x + 3) A = x2 + 3x + 4x + 12 A = x2 + 7x + 12

  9. + 2 Multiplying Pairs of Brackets (x + 2)(x + 3) ( x ) (x + 3) (x + 3) = x2 + 3x + 2x + 6 = x2 + 5x + 6 =

  10. + 4 Multiplying Pairs of Brackets (y + 4)(y - 3) ( y ) (y - 3) (y - 3) = y2 – 3y + 4y - 12 = y2 + y - 12 =

  11. - 5 Multiplying Pairs of Brackets (z - 5)(z + 1) ( z ) (z + 1) (z + 1) = z2 + z – 5z - 5 = z2 – 4z - 5 =

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