430 likes | 566 Views
EIE 696/ENE 623 Optical Communication. Lecture 2. Optical loss or attenuation. P in = 1 mW , P out = 0.1 mW L(dB) = 10 dB P in = 1 mW , P out = 10 -5 mW L(dB) = ___ dB. Optical loss or attenuation. L(dB) = 10 P out = 0.1 P in L(dB) = 50 P out = .
E N D
EIE 696/ENE 623 Optical Communication Lecture 2
Optical loss or attenuation • Pin = 1 mW, Pout = 0.1 mW L(dB) = 10 dB • Pin = 1 mW, Pout = 10-5mW L(dB) = ___ dB
Optical loss or attenuation • L(dB) = 10 Pout = 0.1 Pin • L(dB) = 50 Pout =
Optical loss or attenuation • Fiber loss at 1550 nm is about 0.2 dB/km If the length is 100 km, the loss will be …..
dBm • Decibels with respect to 1 mW. • For example, P = 1mW -30 dB = ……. dBm
Excess Loss (multiport devices) • Multiport device such as directional coupler.
Excess Loss (multiport devices) • For example, • Therefore, Pout/Pin = 0.8 loss 1 dB Pout/Pin = 0.5 loss 3 dB
Coherence length • The length in space corresponding to the bandwidth of the source’s spectrum. where vg = group velocity B = bandwidth
Birefringence and beat length • In a long fiber, a slight birefringence causes a shift of relative phase shift. This leads to a change in relative strengths of Ex and Ey. • Beat length is the length which wave travels before the phase shift completes a change of 2.
Birefringence and beat length where Lbeat= beat length = 2n ‘0’ = ordinary wave ‘e’ = extraordinary wave Source: ARC Electronics http://www.arcelect.com/fibercable.htm
Fiber Network Topologies • Star Network • Linear Bus Network • Tree Network
Star Network Source: Fiber Optic Network Paul E. Green, Prentice Hall.
Fiber Network Topologies • For an ideal star coupler (with no excess loss), power splits equally among terminals.
Linear Bus Network • Directional couplers are used to tap data from the bus.
Directional Coupler • Consider case of input at port 1 • Not all input at port 1, necessarily emerges at remaining ports, this leads to definition of losses encountered in DC. P1 P2 P3 P4
Directional Coupler • Throughput loss(LTHP): This is the loss encountered in going straight through expressed in dB. • TAP loss (LTAP): This is the loss encountered in crossing over expressed in dB.
Directional Coupler • Excess loss (LE): If P1 P2 + P3 then • Directionality loss (LD): If P4 0 then
Directional Coupler • Sometimes, DC is specified by their splitting ratio. (i.e. P2/P3) - For example, splitting ratio =1:1 P2/P3 = 1;therefore, P2= P3 splitting ratio =8:1 P2/P3 = 8;therefore, P2= 8P3
Directional Coupler • An ideal DC is one with P1 = P2 + P3 LE = 0 dB P4 = 0 LD = dB • Suppliers provide DCs by describing their LTAP. • For example, LTAP = 3 dB implies P3 is 3-dB down, or LTAP = 10 dB implies P3 is 10-dB down.
Example 1 • Light source gives 107 photons/bit interval while a receiver requires at least 103 photons/bit interval. If a star coupler and directional coupler used in this network are having excess loss of 10 dB and 1 dB, respectively. How many terminals could this network have?
Power Budget Source: Optical Fiber Communications, G.Keiser, McGraw Hill.
Combiners • N x 1 coupler • Ideal case: Pout = Pin with multimode fiber at output no excess loss. • With a single mode fiber, the best possible result is Pout = Pin /N. Excess loss will be 10log10N.
Splitters • 1 x N coupler • (Pout)j = Pin/N. • Loss = 10log10N for both single and multi-mode fibers. • Excess loss will be …. dB.
Data Transmission Formats • WDMA = Wavelength Division Multiple Access • TDMA = Time Division Multiple Access • CDMA = Code Division Multiple Access
Optical power and numbers of photons. • It is important to understand the relationship between an optical power and number of photons/time or number of photons/bit.
Optical power and numbers of photons. • For λ = 1.24 μm, hν = 1 eV or 1.6 x 10-19 J. • This replies that 1 W of optical power give the same number of photons per sec as 1 A of electrons per second. • 1 A = 1/e = 6.3 x 1018 electrons/s
Reflections at plane boundary • Normal incidence The reflection coefficient, , can be written as where = the ratio of the reflected electric field to the incident electric field
Reflections at plane boundary Reflectance or Reflectivity *From the conservation of energy, R + T = 1 where T = transmittance.
Reflections at plane boundary Ex. Calculate transmittance, T, into fiber from air Soln T + R = 1 air Fiber; n = 1.5
Reflections at plane boundary • Oblique incidence • If the electric field is polarized perpendicular to the incident plane, it is called “s-polarization”. • If the electric field is polarized parallel to the plane of incidence, this is called “p-polarization”.
Reflections at plane boundary Fresnel’s laws of reflection
Reflections at plane boundary • Zero reflection (R=0) occurs only for the p-polarization at the angle called “Brewster angle”. • There is no incident angle that will make s = 0.
Reflections at plane boundary • In case of =1, which occurs at • Therefore, critical angle can be found as
Numerical Aperture • NA identifies the largest angle which light can be coupled to the waveguide, so that rays will be guided as modes in the waveguide.
Numerical Aperture • Snell’s law:
Numerical Aperture • As we know no TIR for < c (cutoff at = c): cis a critical angle.
Optical Fibers Single-mode fiber Multi-mode fiber Source: Fiber Optic Network Paul E. Green, Prentice Hall.
Optical Fibers • Three properties of fibers give them an edge over other media as a communication technology • Large bandwidth • Low attenuation • Small size • Immune to EM
Optical Fibers • Fibers are made from one of the most plentiful materials on earth which is ……… • This is a win-win situation in both cost and environment. • “The same ton of coal required to produce 90 miles of copper wire can turn out 80,000 miles of fiber.” A. Toffler, The 3rd Wave, 1980.
Optical Fibers • Refractive index (n): This relates to a phase velocity in a medium. • where c = speed of light in free space (air) = 3x108 m/s v = light velocity in any medium • Note: The frequency will not change when the medium is changed, but the wavelength will do.
Optical Fibers Snell’s law: