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Chapter 18. Capacitors January, 30 th , 2013 . Electric Flux. Field lines penetrating an area A. The flux , Φ is: Φ E = E A cos θ The normal to the area A is at an angle θ to the field If the area encloses a volume:
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Chapter 18 Capacitors January, 30th, 2013
Electric Flux • Field lines penetrating an area A. • The flux, Φ is: ΦE= E A cosθ • The normal to the area A is at an angle θ to the field • If the area encloses a volume: • for E-field lines that go into the volume, the flux is negative • for E-field lines coming out of the volume the flux is positive
Gauss’s Law • Gauss’s Law: the electric flux through any closed surface is equal to the net charge Q inside the surface divided by εo • The constant εo is the permittivity of free space (εo=8.85 x 10-12 C2/Nm2) • The area used for Φ is an imaginary surface, a Gaussian surface, it does not have to coincide with the surface of a physical object
Electric Field: Flat Sheet of Charge • The large, flat sheet of charge has a charge per unit area = • The flux through the sides of the surface is zero (cosq=0) • Through each end, E = EA • Since there are two ends, E = 2EA
Flat Sheet of Charge, cont. • The total charge is equal to the charge/area multiplied by the cross-sectional area of the cylinder • q = A • Therefore, the electric field is • Note, the E-field is uniform everywhere on the sheet or other planes parallel to it, and does not depend on the distance from the sheet
Capacitor • A capacitor consists of two parallel metal plates that carry charges of +Q and –Q • The excess charge on the two plates will attract each other and draw all the excess charge to the inner sides of the two plates
Capacitor, cont. • Each plate has an area A and charge densities of + = +Q/A and - = -Q/A • Inside the capacitor: • The E-field is • The E-field is constant everywhere • The voltage drops V as +- • You can store energy in a capacitor (problem: the charge drops rapidly)
Capacitors • A capacitor can be used to store charge and energy • This example is a parallel-plate capacitor • Connect the two metal plates to wires that can carry charge on or off the plates
Capacitors, cont. • Each plate produces a field E = Q / (2 εo A) • In the region between the plates, the fields from the two plates add, giving • This is the electric field between the plates of a parallel-plate capacitor • There is a potential difference across the plates • ΔV = Ed where d is the distance between the plates
Capacitance Defined • From the equations for electric field and potential, • Capacitance, C, is defined as • In terms of C, • A is the area of a single plate and d is the plates’ separation
demos Variation of voltage with plate separation Sample capacitors
demos Leyden jar and shorting wand Dissectible Leyden jar
Capacitance, Notes • Other configurations will have other specific equations • All will employ two plates of some sort • In all cases, the charge on the capacitor plates is proportional to the potential difference across the plates • the SI unit of capacitance is Coulomb/Volt, called the Farad • 1 F = 1 C/V • The Farad is named in honor of Michael Faraday (English, 1791-1867)
Storing Energy in a Capacitor • The use of capacitors depends on the capacitor’s ability to store energy and the relationship between charge and potential difference (voltage) • When there is a nonzero potential difference between the two plates, energy is stored in the device • The energy depends on the charge, the voltage, and the capacitance of the capacitor
Energy in a Capacitor, cont. • To move a charge ΔQ through a potential difference ΔV requires energy • The energy corresponds to the shaded area in the graph • The total energy stored is equal to the energy required to move all the packets of charge from one plate to the other
Energy in a Capacitor, Final • The total energy corresponds to the area under the ΔV – Q graph • Energy = Area = ½ QΔV = PEcap • Q is the final charge • ΔV is the final potential difference • From the definition of capacitance, the energy can be expressed in different forms • These expressions are valid for all types of capacitors • supercapacitor : http://www.batteryuniversity.com/partone-8.htm
Capacitors in Series • When dealing with multiple capacitors, the equivalent capacitance is useful • In series: • ΔVtotal = ΔVtop (1) +ΔVbottom (2)and remember that
Capacitors in Parallel • When dealing with multiple capacitors, the equivalent capacitance is useful • In parallel: • Qtotal = Q1 +Q2 and Cequiv = C1 +C2 remember that
Combinations of Three or More Capacitors • For capacitors in parallel: Cequiv = C1 +C2 + C3 + … • For capacitors in series: • These results apply to all types of capacitors • When a circuit contains capacitors in both series and parallel, the above rules apply to the appropriate combinations • A single equivalent capacitance can be found up to here 1
Problem 18.71 A defibrillator containing a 20 µF capacitor is used to shock the heart of a patient by attaching its plates to the patient’s chest. Just before discharging, the capacitor has a potential difference of 10,000 V across its plates. (a) what is the energy released into the patient? (b) If the energy is discharged over 20 ms, what is the power output of the defibrillator?
Dielectrics • Most real capacitors contain two metal “plates” separated by a thin insulating region • Many times these plates are rolled into cylinders • The region between the plates typically contains a material called a dielectric
Dielectrics, cont. • Adding a dielectric btw the plates of a capacitor increases the capacitance by a factor κ • and reduces the electric fieldinside the capacitor by a factor κ • The actual value of the dielectric constant κdepends on the material
Dielectrics, final • When the plates of a capacitor are charged, the electric field is established in the dielectric material • Most good dielectrics are highly ionic, thus charges separate inside the dielectric • As a result the charge, the E-field, the voltage all decreasewith time
Dielectric Summary • The results of adding a dielectric to a capacitor apply to any type of capacitor • Adding a dielectric increases the capacitance by a factor κ • Adding a dielectric reduces the electric fieldinside the capacitor by a factor κ • The actual value of the dielectric constantκdepends on the material
Dielectric Breakdown • As more and more charge is added to a capacitor, the electric field increases • For a capacitor containing a dielectric, the field can become so large that it rips the ions in the dielectric apart • This effect is called dielectric breakdown • The free ions are able to move through the material • They move rapidly toward the oppositely charged plate, and destroy the capacitor • The value of the field at which this occurs depends on the material • See table 18.1 for the values for various materials
Lightning • During a lightning strike, large amounts of electric charge move between a cloud (-) and the surface of the Earth (+), or between clouds • There is a dielectric breakdown of the air
Lightning • A man struck by lightning (Lichtenberg figure) http://205.243.100.155/frames/lichtenbergs.html
Lightning • A golf course struck by lightning (Lichtenberg figure) http://205.243.100.155/frames/lichtenbergs.html
Lightning, cont. • Most charge motion involves electrons • They are easier to move than protons • The electric field of a lightning strike is directed from the Earth to the cloud • After the dielectric breakdown, electrons travel from the cloud to the Earth
Lightning, final • In a thunderstorm, the water droplets and ice crystals gain a negative charge as they move in the cloud • They carry the negative charge to the bottom of the cloud • This leaves the top of the cloud positively charged • The negative charges in the bottom of the cloud repel electrons from the Earth’s surface • This causes the Earth’s surface to be positively charged and establishes an electric field similar to the field between the plates of a capacitor • Eventually the field increases enough to cause dielectric breakdown, which is the lightning bolt
t d Question Consider a capacitor made of two parallel metallic plates separated by a distance d. A new metal plate with thickness t is inserted between them without changing the charge on the original plates. The capacitance of the capacitor 1) increases 2) decreases 3) stays the same Effective “d” decreasesC = εoA/d increases up to here 2
t d Question Consider a capacitor made of two parallel metallic plates separated by a distance d. A dielectric slab with thickness t is inserted between them without changing the charge on the original plates. The energy stored in the capacitor 1) increases 2) decreases 3) stays the same Effective “εo”, or ε, increasesC=εA/d increasesEcap=Q2/2C decreases
Question - - - - + + + + -q +q d pull pull A parallel plate capacitor is given a charge q. The plates are then pulled a smalldistance further apart. What happens to the charge q on each plate of the capacitor? 1) Increases 2) Stays constant 3) Decreases Remember that charge is real/physical. There is no place for the charges to go.
Electric Potential Energy Revisited • One way to view electric potential energy is that the potential energy is stored in the electric field itself • Whenever an electric field is present in a region of space, potential energy is located in that region • The potential energy between the plates of a parallel plate capacitor can be determined in terms of the field between the plates:
Electric Potential Energy, final • The energy density of the electric field can be defined as the energy / volume: • These results give the energy density for any arrangement of charges • Potential energy is present whenever an electric field is present